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1 year ago

To heat the house, the boiler transfers 15 MJ of energy in 10 minutes.

1 answer:

8 0

The formula is P = E/t, where P means power in watts, E means energy j , and t means time in seconds. This formula states that power is the consumption of energy per unit of time.

P = 15 M / 10*60

M = mega = 10⁶

15 *10⁶ / 600

= 25000 watt

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Convert 5.7 miles to km

gayaneshka [121]

5.7 kilometers is equal to 3.5418157957528034 miles

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2 years ago

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A diffraction grating has 500 slits/mm. What is the longest wavelength of light for which there will be a third-order maximum?

Alexxandr [17]

Answer:

The longest wavelength of light is 666.7 nm

Explanation:

The general form of the grating equation is

mλ = d(sinθi + sinθr)

where;

m is third-order maximum = 3

λ is the wavelength,

d is the slit spacing (m/slit)

θi is the incident angle

θr is the diffracted angle

Note: at longest wavelength, sinθi + sinθr = 1

λ = d/m

d = 1/500 slits/mm

λ = 1 mm/(500 *3) = 1mm/1500 = 666.7 X 10⁻⁶ mm = 666.7 nm

Therefore, the longest wavelength of light is 666.7 nm

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3 years ago

Fluorescence occurs when an object absorbs ____________________ and immediately releases the energy as visible light.

soldier1979 [14.2K]

Answer:

The answer should be light or other electromagnetic radiation

Explanation:

Such as x-rays or other things like that.

-Hope This Helps!

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1 year ago

A dog has a mass of 60kg and an acceleration of 2m/s/s. What is the force of the dog?

attashe74 [19]

Answer:

120 N

Explanation:

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2 years ago

A bucket of water of mass 10 kg is pulled at constant velocity up to a platform 30 meters above the ground. This takes 10 minute

Rudik [331]

Answer:

W = 2352 J

Explanation:

Given that:

mass of the bucket, M = 10 kg

velocity of pulling the bucket, v = 3 $m.min^{-1}$

height of the platform, h = 30 m

time taken, t = 10 min

rate of loss of water-mass, m = $0.4 kg.min^{-1}$

Here, according to the given situation the bucket moves at the rate,

$v=3 m.min^{-1}$

The mass varies with the time as,

$M=(10-0.4t) kg$

Consider the time interval between t and t + ∆t. During this time the bucket moves a distance

∆x = 3∆t meters

So, during this interval change in work done,

∆W = m.g∆x

For work calculation:

$W=\int_{0}^{10} [(10-0.4t).g\times 3] dt$

$W= 3\times 9.8\times [10t-\frac{0.4t^{2}}{2}]^{10}_{0}$

$W= 2352 J$

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2 years ago