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Vitek1552 [10]
3 years ago
6

A cook had a jar containing a sweet food and a jar containing a sour food. The sweet food has a strong attraction between its mo

lecules, and the sour food has a weak attraction between its molecules. At room temperature, both foods are liquids. The cook left both jars in a place where the same amount of energy was transferred into both substances. When she returned, one of the foods had changed phase while the other had not. Which food changed phase, and how did it change?
Physics
1 answer:
patriot [66]3 years ago
7 0

Answer:

The sweet food changed because the molecules were able to move fast enough to overcome the attraction between them with its molecules now moving away from each other.

Explanation:

We are told that the sweet food has a strong attraction between its molecules, and the sour food has a weak attraction between its molecules.

This means that the molecules in the sweet food would be moving at a faster rate than in the sour food because of the strong forces of attraction. Therefore, the molecules in the sweet food would be moving far away from each other hence the change of phase.

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Explanation:

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A uniform electric field of magnitude 4.6 ✕ 104 N/C is perpendicular to a square sheet with sides 3.0 m long. What is the electr
rodikova [14]

Answer:

41.4* 10^4 N.m^2/C

Explanation:

given:

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then electric flux = ∫ E*n dA

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Which is 20 miles per hour north an example of?
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3 years ago
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PlzHELP
Naddika [18.5K]
 Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion.Displacement<span> is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

</span>To calculate displacement<span>, simply draw a vector from your starting point to your final position and solve for the length of this line. If your starting and ending position are the same, like your circular 5K route, then your </span>displacement<span> is 0. In physics, </span>displacement<span> is represented by Δs.
 
 For me to solve this I would need to know the time, but I can give you a handy displacement calculator I used that helped me. 
 
https://www.easycalculation.com/physics/classical-physics/constant-acc-displacement.php

Hope I helped. 

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8 0
3 years ago
A set of charged plates 0.00262 m apart has an electric field of 155 N/C between them. What is the potential difference between
mylen [45]

Answer: The potential difference between the plates = 0.4061V

Explanation:

Given that the

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Cross multiply

V = 155 × 0.00262

V = 0.4061 V

The potential difference between the plates is 0.4061 V

5 0
3 years ago
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