Answer:
= 14.88 N
Explanation:
Let's begin by listing out the given variables:
M = 2.7 kg, L = 3 m, m = 1.35 kg, d = 0.6 m,
g = 9.8 m/s²
At equilibrium, the sum of all external torque acting on an object equals zero
τ(net) = 0
Taking moment about
we have:
(M + m) g * 0.5L -
(L - d) = 0
⇒
= [(M + m) g * 0.5L] ÷ (L - d)
= [(2.7 + 1.35) * 9.8 * 0.5(3)] ÷ (3 - 0.6)
= 59.535 ÷ 2.4
= 24.80625 N ≈ 24.81 N
Weight of bar(W) = M * g = 2.7 * 9.8 = 26.46 N
Weight of monkey(w) = m * g = 1.35 * 9.8 = 13.23 N
Using sum of equilibrium in the vertical direction, we have:
+
= W + w ------- Eqn 1
Substituting T2, W & w into the Eqn 1
+ 24.81 = 26.46 + 13.23
= <u>14.88</u> N
Answer:
v = 306.76 Km/h
Explanation:
given,
height of the aircraft = 3000 m
differential pressure reading = 3300 N/m²
density of air = 0.909 Kg/m³
speed of aircraft = ?
Assuming the air flowing above air craft is in-compressible, irrotational and steady so, we can use Bernoulli's equation to solve the problem.
using Bernoulli's equation

where ρ is the density of the air at 3000 m



v = 85.21 m/s

v = 306.76 Km/h
Answer:
I think the answer is ST. Option B
Answer:
The answer to your question is at the point where it is thrown.
Explanation:
Kinetic energy is the energy that possesses a body due to its motion. Its formula is
Ke = 1/2 mv²
Then, the kinetic energy is maximum when the velocity is the highest, and this is at the point where it is thrown, after this point, the velocity will be diminished and at the highest point will be equal to zero.
Answer:
A. Rocket A will travel farther horizontally than rocket B.
Explanation:
This is because from the x axis, 40 m/s at 90 degrees travels directly vertical. 40 m/s at 70 degrees is slightly horizontal, so it will travel further horizontally.