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Liula [17]
3 years ago
9

Consider a ball thrown straight up in the air. At what position is its kinetic energy a maximum?

Physics
2 answers:
Lady_Fox [76]3 years ago
7 0

Answer:

The answer to your question is at the point where it is thrown.

Explanation:

Kinetic energy is the energy that possesses a body due to its motion. Its formula is

          Ke = 1/2 mv²

Then, the kinetic energy is maximum when the velocity is the highest, and this is at the point where it is thrown, after this point, the velocity will be diminished and at the highest point will be equal to zero.

Aliun [14]3 years ago
6 0

Answer:

Explanation:

When a body is thrown upward, the body has it maximum velocity with the velocity of the throw and this velocity keep decreasing due to deceleration that is cause by acceleration due to gravity until it gets to the maximum height where the velocity is zero.

Since kinetic energy is determine by.

K.E = ½mv²

The mass of the body is constant all through.

Then, the maximum velocity is at the point of thrown, then the body has it maximum kinetic energy at the point of throw.

If we considered when it is landing too

It will have a maximum velocity at the point of throw again, where it lands on the hand.

The same kinetic energy will be recorded at the point of thrown and at the point it landed on his hands back.

This is why it has been recorded that, a straight bullet fired upward can kill someone at the point of return, because it will land at the same velocity it left the ground

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Suppose a soccer player kicks the ball from a distance 29 m toward the goal. find the initial speed of the ball if it just passe
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The ball's vertical velocity at the time it just passes over the goal is 0 m/s. Its initial vertical velocity is unknown and we denote it by v\sin39^\circ, where v here is the ball's initial speed. Vertically, the only force acting on the ball is gravity, which attributes a downward acceleration of 9.8 m/s^2. We expect the maximum height achieved by the ball to be 2.4 m, so we can find the initial speed by solving

\left(0\,\dfrac{\mathrm m}{\mathrm s}\right)^2-\left(v\sin39^\circ\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm m)

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What is the name of the compound that goes with the chemical formula MgCl2
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8 0
3 years ago
1. Define weight
andrezito [222]

1. Weight is the gravitational pull with which the earth attracts the body towards the center of the earth. The S.I unit is Newton (N)

2. The weight of an object is related to its mass with the below equation.

W = mg

Where W = weight, m = mass and g = acceleration due to gravity

3. The mass m = 50 kg and g = 9.8 m/s^{2}

Substitute the parameters in the equation above.

W = 50 x 9.8

W = 490 N

4. An object is accelerating when it speeds up. If the object slows down, it means it is decelerating. The correct answer is option A

5. Newton's second law of motion is:

F = ma

Where F = force applied, m = mass and a = acceleration

Therefore, Newton's second law of motion relates an object's acceleration to its net force acting on it. The correct answer is option C

6. According to Newton's second law of motion which relates an object's acceleration to its mass, doubling the net force acting on an object a doubles its acceleration. Because mass is always constant.

7. Since the weight of an object is related to its mass with the equation.

W = mg,  If the mass of an object doubles, its weight will also doubles. Option A is the correct answer.

8. If you know the mass of an object, you can calculate its weight with the formula F = mX when X = 9.8m/s^{2}

9. Force is expressed in unit as Newton (N)

10. The parameters given are :

mass m = 20kg

Force F = 40N

To calculate acceleration, use the formula F = ma

Substitute all the parameters into the equation.

40 = 20a

a = 40/20

a = 2m/s^{2}

The correct option is D

Learn more here : brainly.com/question/18835375

8 0
3 years ago
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