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Liula [17]
3 years ago
9

Consider a ball thrown straight up in the air. At what position is its kinetic energy a maximum?

Physics
2 answers:
Lady_Fox [76]3 years ago
7 0

Answer:

The answer to your question is at the point where it is thrown.

Explanation:

Kinetic energy is the energy that possesses a body due to its motion. Its formula is

          Ke = 1/2 mv²

Then, the kinetic energy is maximum when the velocity is the highest, and this is at the point where it is thrown, after this point, the velocity will be diminished and at the highest point will be equal to zero.

Aliun [14]3 years ago
6 0

Answer:

Explanation:

When a body is thrown upward, the body has it maximum velocity with the velocity of the throw and this velocity keep decreasing due to deceleration that is cause by acceleration due to gravity until it gets to the maximum height where the velocity is zero.

Since kinetic energy is determine by.

K.E = ½mv²

The mass of the body is constant all through.

Then, the maximum velocity is at the point of thrown, then the body has it maximum kinetic energy at the point of throw.

If we considered when it is landing too

It will have a maximum velocity at the point of throw again, where it lands on the hand.

The same kinetic energy will be recorded at the point of thrown and at the point it landed on his hands back.

This is why it has been recorded that, a straight bullet fired upward can kill someone at the point of return, because it will land at the same velocity it left the ground

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Which of the following describes a heat sink?
Zielflug [23.3K]

Answer:

B. A device that absorbs and draws heat from a hot object,

dispersing it into the surroundings

Explanation

a heat sink is an object that disperses heat from another object. They're most commonly used in computers, but are also found in cell phones , DVD players and even refrigerators. In computers, a heat sink is an attachment for a chip that prevents the chip from overheating and, in modern computers, it's as important as any other component.

3 0
3 years ago
To maintain the same amount of torque due to a mass on a balance as the mass is increased, how should the position of the mass c
olasank [31]

Answer:

the mass should be bring closer to the point about which we are finding torque

Explanation:

τ = Σr × F = rmg

where m is the mass, g is acceleration due to gravity, and r is the distance

Torque is directly proportional to -

1.mass, m , of object

2. distance, r, of the mass from the point about which we are finding the torque.

So if we increase or decrease them then the torque will also increase or decrease.

So if we increase the mass the torque will increase but since we have to maintain same torque therefore we have to decrease the distance of mass from the point about which we are finding torque.

Therefore the mass should be bring closer to the point about which we are finding torque.

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3 years ago
Which of the following is a mood disorder?
gulaghasi [49]
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5 0
3 years ago
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What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged partic
VladimirAG [237]

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

A

   v_w  =  2.256 *10^{8} \  m/s

B

  v_e  =  2.21 *10^{8} \  m/s

C

The  correct option is  B  

Explanation:

From the question we are told that

      The refractive  index of water is  n_w  =  1.33

      The  refractive  index of ethanol is  n_e  =  1.36

       

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

       v_w  =  \frac{c}{n_w }

Where  c is the speed of light with value  c =  3.0 *10^{8} \  m/s

       v_w  =  \frac{3.0 *10^{8}}{1.33 }

       v_w  =  2.256 *10^{8} \  m/s

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

            v_e  =  \frac{ c}{n_e }

  =>       v_e  =  \frac{3.0 *10^{8}}{1.36 }

=>          v_e  =  2.21 *10^{8} \  m/s

4 0
3 years ago
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