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3 years ago

14

Bone has a Young’s modulus of about

1 answer:

MArishka [77]3 years ago

6 0

Answer:

Explanation:

Bone has a Young’s modulus of about

1.8 × 1010 Pa . Under compression, it can

withstand a stress of about 1.66 × 108 Pa before breaking.

Assume that a femur (thigh bone) is 0.56 m

long, and calculate the amount of compression

this bone can withstand before breakin :).

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An automobile starter motor has an equivalent resistance of 0.055 Ï and is supplied by a 12.0 v battery which has a 0.0305 Ï int

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12 V is the f.e.m. $\epsilon$ of the battery. The potential difference that is applied to the motor is actually the fem minus the voltage drop on the internal resistance r:
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this is equal to the voltage drop on the resistance of the motor R:
$RI$
so we can write:
$\epsilon - Ir = RI$
and using $r=0.0305~\Omega$ and $R=0.055~\Omega$ we can find the current I:
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3 years ago

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2 years ago

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A boat is traveling at an initial velocity of 2.7 meters per second in the positive direction. It accelerates at a rate of 0.15

cupoosta [38]

Answer:

$\boxed {\boxed {\sf 4.5 \ m/s \ in \ the \ positive \ direction}}$

Explanation:

We are asked to find the final velocity of the boat.

We are given the initial velocity, acceleration, and time. Therefore, we will use the following kinematic equation.

$v_f= v_i + at$

The initial velocity is 2.7 meters per second. The acceleration is 0.15 meters per second squared. The time is 12 seconds.

$v_i$ = 2.7 m/s
a= 0.15 m/s²
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Substitute the values into the formula.

$v_f = 2.7 \ m/s + (0.15 \ m/s^2)(12 \ s)$

Multiply the numbers in parentheses.

$v_f= 2.7 \ m/s + (0.15 \ m/s/s * 12 \ s)$

$v_f = 2.7 \ m/s + (0.15 \ m/s *12)$

$\v_f=2.7 \ m/s + (1.8 \ m/s)$ $v_f=2.7 \ m/s + (1.8 \ m/s)$

Add.

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The final velocity of the boat is <u>4.5 meters per second in the positive direction.</u>

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2 years ago

Determine the magnitude of the electrostatic force on a 0.06000 C charged object when it is placed in an electric field of magni

joja [24]

Answer:

Explanation:

Use the following equation:

$E=\frac{q}{F}$ and solve for F:

$F=\frac{q}{E}$ and filling in:

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2 years ago

The two blocks in oscillate on a frictionless surface with a period of 1.5 s. The upper block just begins to slip when the ampli

Setler79 [48]

Answer:

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Explanation:

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frictional force is given as

$f = \mu mg$

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2 years ago