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irinina [24]
3 years ago
10

Solve for x (3x+4)+2(3x+4)=117

Mathematics
1 answer:
dexar [7]3 years ago
4 0
<h2>(3x+4)+2(3x+4)=117</h2>

<h2>= (3x+4)+(6x+8)=117</h2><h2>= 3x+4+6x+8=117</h2><h2>= 9x+12=117</h2><h2>= 9x = 117-12 </h2><h2>= 9x = 105</h2><h2>= x =105 ÷ 9</h2><h2>= x = 11.6666666667</h2>

<h2>Hence,x = 11.6666666667</h2>

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DerKrebs [107]

Answer:

B is the answer hope you get it right

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3 years ago
!GET 10 OR 15 POINTS!<br>Steven bag 52 pounds of potatoes . About what is the measure in kilometers?
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Solve the quadratic equation (2x+5)(2x-5)
mote1985 [20]
If you want to multiply (2*x + 5) and (2*x - 5), you can do this using the following steps:

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4 0
3 years ago
Line segment YV of rectangle YVWX measures 24 units.
oksian1 [2.3K]

Answer: YX=13.85\ units

Step-by-step explanation:

<h3> The complete exercise is: "Line segment YV of rectangle YVWX measures 24 units. What is the length of line segment YX?"</h3><h3> The missing figure is attached.</h3>

Since the figure is a rectangle, you know that:

WV=YX\\\\YV=XW=24

Notice that the segment YV divides the rectangle into two equal Right triangles.

Knowing the above, you can use the following Trigonometric Identity:

tan\alpha =\frac{opposite}{adjacent}

You can identify that:

\alpha =30\°\\\\opposite=YX\\\\adjacent=YV=24

Therefore, in order to find the length of the segment YX, you must substitute values into  tan\alpha =\frac{opposite}{adjacent} and then you must solve for YX.

You get that this is:

tan(30\°)=\frac{YX}{24}\\\\(24)(tan(30\°))=YX\\\\YX=13.85

7 0
3 years ago
Read 2 more answers
A 20-ft-long wire is used to support a television antaans. The wire is connected to the
MariettaO [177]

Answer:

The distance of base of wire to the base of tower is 13.27 ft

Step-by-step explanation:

Given as :

The measure of wire connected between base ad antenna top = 20 ft

The wire is connected to the  antenna on tower at height h = 15 ft above the ground

Let The distance of base of wire to the base of tower = x ft

Let the angle drawn on ground = Ф

Now, According to question

<u>In figure AOB</u>

Sin angle = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

i.e SinФ = \dfrac{\textrm AB}{\textrm BO}

Or,  SinФ = \dfrac{\textrm h}{\textrm 20}

Or,  SinФ = \dfrac{\textrm 15}{\textrm 20}

Or, SinФ = \dfrac{\textrm 3}{\textrm 4}

or, Ф = sin^{-1}(\frac{3}{4})

∴ Ф = 48.5°

<u>Now, Again from figure</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

i.e TanФ = \dfrac{\textrm AB}{\textrm OA}

Or, Tan 48.5° = \dfrac{\textrm h}{\textrm x}

Or, 1.13 = \dfrac{\textrm 15}{\textrm x}

∴ x = \dfrac{\textrm 15}{\textrm 1.13}

i.e x = 13.27 feet

So, The distance of base of wire to the base of tower = x = 13.27 ft

Hence, The distance of base of wire to the base of tower is 13.27 ft Answer

5 0
4 years ago
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