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Solnce55 [7]
3 years ago
15

What is the third quartile of the given data set? {2, 5 ,6, 7, 15, 16, 17}

Mathematics
1 answer:
Tanya [424]3 years ago
5 0
Series = <span>{2, 5 ,6, 7, 15, 16, 17}

Here, Median = 7

Then Q3 = </span><span>{15, 16, 17}
Median of Q3 = 16

In short, Your Answer would be: 16

Hope this helps!</span>
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A car rental company offers the following two plans for renting a car:
AveGali [126]

Answer:

181.818181...Miles

Step-by-step explanation:

50 = 30 + 11X

X = 181.81818181...

If you multiply 11 by 181.81 repeting you will get 20 and 30 + 20 = 50

So You would have to go 181.81 repeating miles for it to be equal

If you are rounding up it would be 182 miles to justify choosing plan B

3 0
2 years ago
A human body that is performing light work generates about 650 BTUs of body heat per hour. If a room that is 10 ft × 12 ft × 9 f
Helen [10]
Your answer should be, BTU / cubic foot = 650 (4) (4) / 5000 = 2.08 BTU / ft^3, Hope this helps you! :D
7 0
2 years ago
Read 2 more answers
How can I simplify 1/2 + 2/3. Do I add,then divide.
IRISSAK [1]
You can converte them to a common denominator like 6. 1/2 would be 3/6. 2/3 would be 4/6.
6 0
3 years ago
Read 2 more answers
Solve for x in the following equation:
Feliz [49]

Answer:

x = 17

Step-by-step explanation:

1) Make the bases the same then rewrite.

4 = 2²

2^2(2x - 5) = 2^3x + 7

2) Since the bases are the same, set the exponents equal to each other.

2(2x -5) = 3x + 7

4x - 10 = 3x + 7

4x - 3x = 7 + 10

x = 17

4 0
1 year ago
Solve the following equation on the interval [0, 2π). tan^2x sin x = tan^2x
Alenkasestr [34]
<h3>Given</h3>

tan(x)²·sin(x) = tan(x)²

<h3>Find</h3>

x on the interval [0, 2π)

<h3>Solution</h3>

Subtract the right side and factor. Then make use of the zero-product rule.

... tan(x)²·sin(x) -tan(x)² = 0

... tan(x)²·(sin(x) -1) = 0

This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:

... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)

Then our equation becomes

... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0

... -sin(x)²/(1 +sin(x)) = 0

Now, we know the only solutions are found where sin(x) = 0, at ...

... x ∈ {0, π}

8 0
3 years ago
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