Answer:
35.9 ml
Explanation:
Start with the balanced equation:
3CuCl2(aq)+2Na3PO4(aq)→Cu3(PO4)2(s)+6NaCl(aq)
This tells us that 3 moles of CuCI2 react with 2 moles Na3PO4-
∴ 1 mole CuCl2 will react with 2/3 moles Na3PO4
We know that concentration = moles/volume i.e:
c= n/v
∴n=c×v
∴nCuCl2=0.107×91.01000=9.737×10−3
I divided by 1000 to convert ml to L
∴nNa3PO4=9.737×10−3×23=6.491×10−3
v=nc=6.491×10−30.181=35.86×10−3L
∴v=35.86ml
Hi,
"Phosphorous is normally found as a solid, but since it reacts with oxygen it is not normally found in an elemental form"
Have a great day!
Answer:
We need 2.02 grams of NH3
Explanation:
Step 1: Data given
Mass of methanol = 475 grams
Molality of the solution = 0.250 M
Molar mass of NH3 =17.03 g/mol
Molar mass of = methanol = 32.04g/mol
Step 2: Calculate moles NH3
Molality = 0.250 m = mol NH3 / 0.475 kg
moles NH3 = 0.250 molal * 0.475 kg
Moles NH3 = 0.11875 moles
Step 3: Calculate the mass of NH3
Mass NH3 = moles NH3 * molar mass NH3
Mass NH3 = 0.11875 mol * 17.03 g/mol
Mass NH3 = 2.02 grams
We need 2.02 grams of NH3
Identify each of the elements. H- Hydrogen, O-Oxygen, C- Carbon. The little number after the letter is the number of that element. H2O- 1 O and CO2- 2 O
