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Sergeeva-Olga [200]
3 years ago
7

Scientific notation for 6.7639104

Chemistry
1 answer:
Liula [17]3 years ago
6 0
6.7639104*10^0 is the answer.
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What are the three forms of water and what are the scientific names when they change into each other
Aleonysh [2.5K]
Solid liquid and gas

when it changes from a:
solid
  to a
     liquid: melting, fusion
     gas: sublimation
liquid
   to a
       solid:freezing
       gas:vaporization
gas
   to a
       solid:condensation, deposition
       liquid: condensation, liquefacation
7 0
3 years ago
Read 2 more answers
is a polyprotic acid. Write balanced chemical equations for the sequence of reactions that carbonic acid can undergo when it's d
Burka [1]

Answer:

H₂CO₃   H₂O  ⇄  HCO₃⁻  +  H₃O⁺          Ka1

HCO₃⁻  +  H₂O  ⇄  CO₃⁻²  +  H₃O⁺        Ka2

CO₃⁻²  +  H₂O  ⇄  HCO₃⁻   +  OH⁻       Kb1

HCO₃⁻  +  H₂O  ⇄   H₂CO₃  +  OH⁻     Kb2

Explanation:

Formula for carbonic acid is: H₂CO₃

It is a dyprotic acid, because it can release two protons. We can also mention that is a weak one. The equilibrums are:

H₂CO₃   H₂O  ⇄  HCO₃⁻  +  H₃O⁺          Ka1

HCO₃⁻  +  H₂O  ⇄  CO₃⁻²  +  H₃O⁺        Ka2

When the conjugate strong bases, carbonate and bicarbonate take a proton from water, the reactions are:

CO₃⁻²  +  H₂O  ⇄  HCO₃⁻   +  OH⁻       Kb1

HCO₃⁻  +  H₂O  ⇄   H₂CO₃  +  OH⁻     Kb2

Notice, that bicarbonate anion can release or take a proton to/from water. This is called amphoteric,

6 0
3 years ago
Which of the following structers is formed when fertilization occurs
kaheart [24]
I believe the answer would be C
5 0
4 years ago
The enthalpy of fusion of H2O (s) at its normal melting point is 6.01 kJ/mol. What is the entropy change for freezing 1 mole of
Rom4ik [11]

Answer:

22.01J/Kmol

Explanation:

The parameters given in this question are;

Enthalpy (H) = 6.01 kJ/mol.

Number of moles = 1

Entropy change (S) = ?

The formular relationship between entropy and enthalpy is given as;

ΔS=ΔH/T

Temperature for water at freezing point = 0C + 273 = 273 K (converting to Kelvin)

ΔS = 6.01/273

ΔS = 0.0220kJ/Kmol

ΔS = 0.02201 * 1000 = 22.01J/Kmol

3 0
3 years ago
People tend to speak more quietly in restaurants than they do when they are having an ordinary conversation Restaurant conversat
MArishka [77]

Answer:

A loud ordinary conversation following the supplied information in the question is about 4500 dB. But, in the official decibel system measure a loud conversation does not overcome 100 dB.

Explanation:

Using the supplied data of the exercise, we say that in a restaurant conversation the value is 45 dB. If we multiply this by 100 we will have a value for a laud ordinary conversation.

45×100 = 4500 dB.

but as I mentioned in the answer, in the official decibel system measure a loud conversation between 2 man reaches a maximal of 100 dB.

6 0
4 years ago
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