What mass (in g) of NH3 must be dissolved in 475 g of methanol to make a 0.250 m solution?
Answer:
We need 2.02 grams of NH3
Explanation:
Step 1: Data given
Mass of methanol = 475 grams
Molality of the solution = 0.250 M
Molar mass of NH3 =17.03 g/mol
Molar mass of = methanol = 32.04g/mol
Step 2: Calculate moles NH3
Molality = 0.250 m = mol NH3 / 0.475 kg
moles NH3 = 0.250 molal * 0.475 kg
Moles NH3 = 0.11875 moles
Step 3: Calculate the mass of NH3
Mass NH3 = moles NH3 * molar mass NH3
Mass NH3 = 0.11875 mol * 17.03 g/mol
Mass NH3 = 2.02 grams
We need 2.02 grams of NH3
Answer:
Atoms=9.033*10^23 atoms
Explanation:
Atoms=no.of miles*Avogadro's no.
Atoms=1.5*6.022*10^23
Atoms=9.033*10^23 atoms

Explanation:
Mass = volume × density
Mass = 652 cm³ × 21.45 g/cm³
= 13985.4 g
Explanation: