Answer:
d. the conjugate base of the weak acid
Explanation:
The strong base (BOH) is completely dissociated in water:
BOH → B⁺ + OH⁻
The resulting conjugate acid (OH⁻) is a weak acid, so it remains in solution as OH⁻ ions.
By other hand, the weak acid (HA) is only slightly dissociated in water:
HA ⇄ H⁺ + A⁻
The resulting conjugate base (A⁻) is a weak base. Thus, it reacts with H⁺ ions from water to form HA, increasing the concentration of OH⁻ ions in the solution.
Therefore, the resulting solution will have a pH > 7 (basic).
Answer:
0.04838J
Explanation:
Heat is a form of energy that is transferred from one body to another as the result of a difference in temperature between the bodies , here heat is added to the water as a result of temperature change of 0.364 degreesC
Given:change in temperature=0.364
Mass of water=0.0318g
But we need specific heat capacity of water which is
4.2 J/g°C
Then we can calculate How much heat is added by using below formula
Energy = Mass * specific heat capacity *(change in temperature)
energy =0.0318g* 4.18g*0.364
=0.04838J
Answer:
This self evaluation helps them to better his sport.
Explanation:
This is the right way to evaluate the performance of John because this sketch shows him the way he perform in the match. Due to this sketch he can better his performance and remove all the mistakes he had done in the match which results in better performance of John in the next match. This self evaluation helps them to better his sport and got new chances in order to select for a better club or national soccer team.
The answer is 0.975 L
Volume = mol/Molarity
We have molarity (0.788 M) and we need mol and volume. Let's first calculate number of moles of CaCl2 in 85.3 g:
Molar mass of CaCl2 is sum of atomic masses of Ca and Cl:
Mr(CaCl2) = Ar(Ca) + 2Ar(Cl) = 40 + 2 * 35.45 = 40 + 70.9 = 110.9 g/mol
So, if 110.9 g are in 1 mol, 85.3 g will be in x mol:
110.9 g : 1 mole = 85.3 g : x
x = 85.3 g * 1 mole / 110.9
x = 0.769 moles
Now, calculate the volume:
V = 0.769/0.788
V = 0.975 L
Given- m= 1.75 g
Now moles of O2 gas= Mass/ Molar mass
n = 1.75/32
V= 2L
P= 1atm
R=0.0821.....Constant
As PV=nRT
=> T=PV/nR
= 1* 2/ (1.75/32)*0.0821 K
= 2*32/1.75* 0.0821 K
= 445.45 K
= (445.45- 273.15) degrees celsius
= 172.30 degrees celsius..... ANSWER
