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Tresset [83]
3 years ago
6

An ionic compound whose aqueous solution conducts an electric current is called a(n) ______________.

Chemistry
2 answers:
kvv77 [185]3 years ago
8 0

Answer:

An ionic compound whose aqueous solution conducts an electric current is called a(n) electrolyte

Explanation:

Electrolytes are substances that contain anions and cations and is therefore able to conduct the electric current.

For example: NaCl

NaCl → Na⁺  +  Cl⁻

Annette [7]3 years ago
4 0

Answer:

electrolyte

Explanation:

ionic chemistry

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Which statements differentiate DNA and RNA? Select three options.
Morgarella [4.7K]

Answer:

A.) DNA is a double helix, and RNA is a single strand.



C.) DNA is involved only in transcription, and RNA is involved in both transcription and translation.



E.) DNA does not have uracil as a nitrogen base, but RNA does have uracil as a nitrogen base.











Explanation:

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2 years ago
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Based on Figure 2, which statement best describes what happens to the amount of matter in the reaction?
scoray [572]

Answer:15 +18

Explanation:15 fuel +18 oxygen + 33 cd

8 0
2 years ago
If 6 moles of A and 2 moles of B are reacted, what is the maximum number of moles of C that can be formed
MaRussiya [10]

The question is incomplete, here is the complete question:

Suppose the reaction is:

A+2B\rightarrow C

If 6 moles of A and 2 moles of B are reacted, what is the maximum number of moles of C that can be formed

<u>Answer:</u> The maximum amount of C produced will be 1 mole

<u>Explanation:</u>

We are given:

Moles of A = 6 moles

Moles of B = 2 moles

For the given chemical reaction:

A+2B\rightarrow C

By Stoichiometry of the reaction:

2 moles of B reacts with 1 mole of A

So, 2 moles of B will react with = \frac{1}{2}\times 2=1 mole of A

As, As, given amount of A is more than the required amount. So, it is considered as an excess reagent.

Thus, B is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of B produces 1 mole of C

So, 2 moles of given B will produce =\frac{1}{2}\times 2=1mol of C

Hence, the maximum amount of C produced will be 1 mole

3 0
3 years ago
During the discussion of gaseous diffusion for enriching uranium, it was claimed that 235UF6 diffuses 0.4% faster than 238UF6. S
Kay [80]

<u>Answer:</u> The below calculations proves that the rate of diffusion of ^{235}UF_6 is 0.4 % faster than the rate of diffusion of ^{238}UF_6

<u>Explanation:</u>

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

We are given:

Molar mass of ^{235}UF_6=349.034348g/mol

Molar mass of ^{238}UF_6=352.041206g/mol

By taking their ratio, we get:

\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{M_{(^{238}UF_6)}}{M_{(^{235}UF_6)}}}

\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{352.041206}{349.034348}}\\\\\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\frac{1.00429816}{1}

From the above relation, it is clear that rate of effusion of ^{235}UF_6 is faster than ^{238}UF_6

Difference in the rate of both the gases, Rate_{(^{235}UF_6)}-Rate_{(^{238}UF_6)}=1.00429816-1=0.00429816

To calculate the percentage increase in the rate, we use the equation:

\%\text{ increase}=\frac{\Delta R}{Rate_{(^{235}UF_6)}}\times 100

Putting values in above equation, we get:

\%\text{ increase}=\frac{0.00429816}{1.00429816}\times 100\\\\\%\text{ increase}=0.4\%

The above calculations proves that the rate of diffusion of ^{235}UF_6 is 0.4 % faster than the rate of diffusion of ^{238}UF_6

3 0
3 years ago
Which of the following statements is true about nuclear power? A) It releases greenhouse gases. B) It does not produce wastes. C
antiseptic1488 [7]

A?

I think its A but I am not 100% sure.

3 0
3 years ago
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