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Studentka2010 [4]
3 years ago
6

A gas occupies 900.0 mL at a temperature of 27.0 . What is the volume at 132.0 °C?

Chemistry
1 answer:
Ronch [10]3 years ago
7 0
V₁ = 900.0 mL

T₁ = 27.0ºC + 273 = 300 K

V₂ = ?

T₂ = 132.0 + 273 = 405 K

V₁ / T₁ = V₂ / T₂

900.0 / 300 = V₂ / 405

300 x V₂ = 405 x 900.0

300 x V₂ = 364500

V₂ = 364500 / 300

V₂ = 1215 mL

hope this helps!
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Answer:

Option E. Zirconium

Explanation:

From the question given above, the following data were obtained:

Length of side (L) of cube = 0.2 cm

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Next, we shall determine the volume of the cube. This can be obtained as follow:

Length of side (L) of cube = 0.2 cm

Volume (V) of the cube =?

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Next, we shall convert 52 mg to g. This can be obtained as follow:

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Therefore,

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Density = 0.052 / 0.008

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7 0
3 years ago
An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective
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Answer:

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Partial pressure of the PCl_3=p_1=13.2 Torr

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At equilibrium after adding chlorine gas:

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At equilbriumm

(13.2-x) Torr     (32.8-x) Torr                        (217.0+x) Torr

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p_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr

p_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr

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\huge \fcolorbox{black}{red}{♛answer♛}

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