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ValentinkaMS [17]
3 years ago
15

How can you tell if 2 functions are inverses of eachother

Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

Remember, if the two graphs are symmetric with respect to the line y = x (mirror images over y = x ), then they are inverse functions. But, we need a way to check without the graphs, because we won't always know what the graphs look like! then f(x) and g(x) are inverse functions.
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Check each equation whose graph is the line that contains the points (4, –7) and (1, 5). y = –4x + 9 y = –4x – 23 y – 1 = –4(x –
maxonik [38]

Answer:

The boys are playing games is a plural change into singularGeorge WashingtonOf the 19 hijackers involved in the 9/11 attacks on the US, how many were Saudis ?1. Which leader unified the Kingdom of Saudi Arabia ?

 William Gifford Palgrave

 Abdullah ibn Rashid

 Abdul Aziz ibn Saud

 Abdul Aziz bin Mithab

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2. In what year did King Abdul Aziz ibn Saud die?

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3. Who succeeded King Abdul Aziz ibn Saud ?

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 T. E. Lawrence

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5. Who was the Saudi Arabian Minister of Oil and Mineral Resources between 1962 and 1986

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6. What was the original source of the wealth of the bin Laden family ?

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 1933

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8 0
2 years ago
Read 2 more answers
Solve for x <br> y=-1/2x=3
ANEK [815]

Answer:

-6

Step-by-step explanation:

x=-6

5 0
3 years ago
Dave has 10 poker chips, 6 of which are red and the other 4 of which are white. Dave likes to stack his chips and flip them over
Marina86 [1]

The number of 10 chips stacks that Dave can make if two stacks are not considered distinct is 110.

The solution

To get the symmetric stacks, one has to subtract the symmetric stacks to know the ones that are asymmetric.

The symmetric are flipped. Given that they are double counted what we have to do is to divide through by 2.

6/2 = 3

10/2 = 5

4/2 = 2

1/2(10C6) - (5C3) + (5C3)

0.5(210-10+10)

= 110

8 0
2 years ago
Could you please help me on question 5
morpeh [17]
Question plz thxs 
your welcome
7 0
3 years ago
Y=x+1<br> y=x^2-1<br><br> please help i don't understand
ololo11 [35]

ANSWER

The solution is

(x=1,y=2),(x=2,y=3)


<u>EXPLANATION</u>

We have

y=x+1---(1)

and


y=x^2-1---(2)


Let us substitute equation (1) in to equation (2). This gives us,

x+1=x^2-1(2)

We rewrite this as a quadratic equation as the highest degree is 2.

x^2-x-1-1=0

This implies that


x^2-x-2=0


we factor to obtain,


x^2+x-2x-2=0


x(x-1)-2(x-1)=0


(x-1)(x-2)=0


This means,

(x-1)=0\:\: or\:\:(x-2)=0

x=1\:\: or\:\:x=2


We substitute this values into any of the above equations, preferably equation (1)


When, x=1, y=1+1=2


When, x=2, y=2+1=3


The solution is

(1,2),(2,3)


8 0
3 years ago
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