If you drive at 50 km/hr for 8 hours, how far will you go?

Scientific notation and graphing 0.0004580 to scientific notation

Vlada [557]

Scientific Notation: 4.580 x 10^-4

Scientific e Notation: 4.580e-4

4 0

3 years ago

Read 2 more answers

Ammonia enters the expansion valve of a refrigeration system at a pressure of 10 bar and a temperature of 22oC and exits at 2.0

KonstantinChe [14]

Answer:

The the quality of the refrigerant at the exit of the expansion valve is 0.179.

Explanation:

Given that,

Initial pressure = 10 bar

Temperature = 22°C

Final pressure = 2.0 bar

We using the value of h

$h = 293.4\ kJ/kg$

The refrigerant during expansion undergoes a throttling process

Therefore, $h_{1}=h_{2}$

We need to calculate the quality of the refrigerant at the exit of the expansion valve

At 2.0 bar,

The property of ammonia

$h_{f}=47.8 kJ/kg$

$h_{g}=1417.7 kJ/kg$

Using formula

$h_{2}=h_{f}+x(h_{g}-h_{f})$

Put the value into the formula

$293.4 =47.8+x(1417.7-47.8)$

$x=\dfrac{293.4-47.8}{1417.7-47.8}$

$x=0.179$

Hence, The the quality of the refrigerant at the exit of the expansion valve is 0.179.

6 0

3 years ago

In a computer-based experiment to study diffraction, the width of the central diffraction peak is 15.20 mm. The wavelength of th

pogonyaev

Answer:

$a = 5.7 \times 10^{-5} m$

Explanation:

As we know that position of first minimum on the either side of central maximum is given as

$a sin\theta = \lambda$

$\theta =sin^{-1} \frac{\lambda}{a}$

so the width of the central maximum is given as

$W = L (2\theta)$

so we have

$15.20 \times 10^{-3} = 0.68 \times 2(sin^{-1} \frac{\lambda}{a})$

so we have

$0.011 = sin^{-1} \frac{\lambda}{a}$

$0.011 = \frac{638 nm}{a}$

$a = 5.7 \times 10^{-5} m$

3 0

4 years ago

An arrow of 43 g moving at 84 m/s to the right, strikes an apple at rest. The arrow sticks to the apple and both travel at 16.8

Aloiza [94]

Answer:

The mass of the apple is 0.172 kg (172 g)

Explanation:

The Law Of Conservation Of Linear Momentum

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is

P=mv.

If we have a system of two bodies, then the total momentum is the sum of both momentums:

$P=m_1v_1+m_2v_2$

If a collision occurs and the velocities change to v', the final momentum is:

$P'=m_1v'_1+m_2v'_2$

Since the total momentum is conserved, then:

P = P'

Or, equivalently:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

If both masses stick together after the collision at a common speed v', then:

$m_1v_1+m_2v_2=(m_1+m_2)v'$

We are given the mass of an arrow m1=43 g = 0.043 kg traveling at v1=84 m/s to the right (positive direction). It strikes an apple of unknown mass m2 originally at rest (v2=0). The common speed after they collide is v'=16.8 m/s.

We need to solve the last equation for m2:

$m_2v_2-m_2v'=m_1v'-m_1v_1$