Answer:
[M L2 T-2]
Explanation:
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Answer:
(d) 2840 A
Explanation:
Threshold frequency can be be calculated using expresion below
(λ)= hc/ Φ
(λ) sodium/ (λ)tungsten = Φtungsten/ Φsodium
But (λ) sodium is given as 5460 A,
Φsodium = 2.3 eV
Φtungsten= 4.4 eV
If we substitute the values we can find
(λ)tungsten.
(λ)tungsten= [(λ) sodium × Φsodium]/ Φtungsten
=( 5460× 2.3)/4.4
= 2854A
Hence, threshold wavelength of tungsten is 2854A
Answer:
The tension in string P is 25 N, while that of Q is 85 N.
Explanation:
Considering the conditions for equilibrium,
i. Total upward force = Total downward force
+
= 110 N
ii. Taking moment about P,
clockwise moment = anticlockwise moment
110 × (2.5 - 0.8) =
× (3 - 0.8)
110 × 1.7 =
× 2.2
187 = 2.2
= 
= 85 N
From the first condition,
+
= 110 N
+ 85 N = 110 N
= 110 - 85
25 N
Therefore, the tension in string P is 25 N while that of Q is 85 N.
Answer: degrees divided by 360
Explanation: