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3 years ago

How do you find the g field at a point between 2 masses?

Physics

1 answer:

Allisa [31]3 years ago

6 0

Answer:

Newton's Law of Gravitation states that the gravitational force ⎯⎯ between two point masses and a distance apart in a vacuum, is attractive, acts along the line joining their centres, and is proportional to the masses and inversely proportional to the square of their separations.

∝2

In the SI system, the constant of proportionality is , the gravitational constant, which has a value of 6.67×10−11Nm2kg−2, and so we may write this as,

The gravitational field is the gravitational force per unit mass that would be exerted on a small (so it doesn't measurably affect the gravitational field) test mass at that point. It is a vector field, and points in the direction of the force that a small test mass would feel at that point. For a point particle of mass , the magnitude of the resultant gravitational field strength , at distance from , is

The gravitational force acting on a mass , which is also sometimes described as its weight in the gravitational field ⎯⎯, is given by:

⎯⎯=⎯⎯

At the surface of the Earth, ⎯⎯ has a magnitude of 2=9.81ms−2, where is the radius of the Earth.

Explanation:I am so(maybe)Big brain...

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Examine the images of the Grand Canyon below. Notice that most of the canyon consists of layers of sedimentary rocks, but if you

Tomtit [17]

Intense temperature and pressure of regional metamorphism

Explanation:

The process that cause the formation of the Vishnu Schist is the intense temperature and pressure as a result of regional metamorphism.

Regional metamorphism is an extensive metamorphism of an area as a result of temperature and pressure changes.
The schist is a foliated metamorphic rock usually found in areas of moderate to high grade temperature and pressure.
The Vishnu schist must have been metamorphosed before the new sediments were deposited on top.

Learn more:

Contact metamorphism brainly.com/question/1970623

#learnwithBrainly

7 0

4 years ago

g A thin-walled hollow cylinder and a solid cylinder, both have same mass 2.0 kg and radius 20 cm, start rolling down from rest

ArbitrLikvidat [17]

Answer:

a. i. 3.43 m/s ii. 2.8 m/s

b. The thin-walled cylinder

Explanation:

a. Find translational speed of each cylinder upon reaching the bottom

The potential energy change of each mass = total kinetic energy gain = translational kinetic energy + rotational kinetic energy

So, mgh = 1/2mv² + 1/2Iω² where m = mass of object = 2.0 kg, g =acceleration due to gravity = 9.8 m/s², h = height of incline = 1.2 m, v = translational velocity of object, I = moment of inertia of object and ω = angular speed = v/r where r = radius of object.

i. translational speed of thin-walled cylinder upon reaching the bottom

So, For the thin-walled cylinder, I = mr², we find its translational velocity, v

So, mgh = 1/2mv² + 1/2Iω²

mgh = 1/2mv² + 1/2(mr²)(v/r)²

mgh = 1/2mv² + 1/2mv²

mgh = mv²

v² = gh

v = √gh

v = √(9.8 m/s² × 1.2 m)

v = √(11.76 m²/s²)

v = 3.43 m/s

ii. translational speed of solid cylinder upon reaching the bottom

So, For the solid cylinder, I = mr²/2, we find its translational velocity, v'

So, mgh = 1/2mv'² + 1/2Iω²

mgh = 1/2mv² + 1/2(mr²/2)(v'/r)²

mgh = 1/2mv'² + mv'²

mgh = 3mv'²/2

v'² = 2gh/3

v' = √(2gh/3)

v' = √(2 × 9.8 m/s² × 1.2 m/3)

v' = √(23.52 m²/s²/3)

v' = √(7.84 m²/s²)

v' = 2.8 m/s

b. Determine which cylinder has the greatest translational speed upon reaching the bottom.

Since v = 3.43 m/s > v'= 2.8 m/s,

the thin-walled cylinder has the greatest translational speed upon reaching the bottom.

3 0

3 years ago

7. A 1.0 kg metal head of a geology hammer strikes a solid rock with a velocity of 5.0 m/s. Assuming all the energy is retained

marta [7]

The increase in temperature of the metal hammer is 0.028 ⁰C.

The given parameters:

mass of the metal hammer, m = 1.0 kg
speed of the hammer, v = 5.0 m/s
specific heat capacity of iron, 450 J/kg⁰C

The increase in temperature of the metal hammer is calculated as follows;

$Q = K.E\\\\mc \Delta T = \frac{1}{2} mv^2\\\\\Delta T = \frac{v^2}{2 c}$

where;

c is the specific heat capacity of the metal hammer

Assuming the metal hammer is iron, c = 450 J/kg⁰C

$\Delta T = \frac{5^2}{2 \times 450} \\\\\Delta T = 0.028 \ ^0C$

Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.

Learn more about heat capacity here: brainly.com/question/16559442

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3 years ago

PLS HELP:)

Monica [59]

The incident ray will have an angle of reflection of 30 degrees (made with a surface normal to the mirror surface). The reflected ray will make an angle of 60 degrees (90 - 30 degrees) with the mirror surface.

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3 years ago

Which of these is the largest? a. star b. nebula c. galaxy d. sun

Keith_Richards [23]

I would say it’s between b and c

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3 years ago

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