Answer:
The temperature coefficient of resistivity for a linear thermistor is 
Explanation:
Given that,
Initial temperature = 0.00°C
Resistance = 75.0 Ω
Final temperature = 525°C
Resistance = 275 Ω
We need to calculate the temperature coefficient of resistivity for a linear thermistor
Using formula for a linear thermistor



Put the value into the formula


Hence, The temperature coefficient of resistivity for a linear thermistor is 
Answer:
F = 2.26 × 10⁻³ N
Explanation:
given,
length of rod = 11 cm
charge = 19 nC
linear charge density = 3.9 x 10⁻⁷ C/m
electric force at 2 cm away.

F = E q

integrating from 0.02 to 0.02 + L
![F= \dfrac{2K\lambda\ q}{L}[ln(0.02+L)-ln(0.002)]](https://tex.z-dn.net/?f=F%3D%20%5Cdfrac%7B2K%5Clambda%5C%20q%7D%7BL%7D%5Bln%280.02%2BL%29-ln%280.002%29%5D)
![F= \dfrac{2\times 9 \times 10^9\times 3.9\times 10^{-7}\times 19 \times 10^{-9}}{0.11}[ln(0.02+0.11)-ln(0.002)]](https://tex.z-dn.net/?f=F%3D%20%5Cdfrac%7B2%5Ctimes%209%20%5Ctimes%2010%5E9%5Ctimes%203.9%5Ctimes%2010%5E%7B-7%7D%5Ctimes%2019%20%5Ctimes%2010%5E%7B-9%7D%7D%7B0.11%7D%5Bln%280.02%2B0.11%29-ln%280.002%29%5D)
F = 2.26 × 10⁻³ N
Answer:
N3+3H2----->3NH2
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Answer:
so throwers new velocity = 2.18032m/s
so catchers new velocity = 0.02577m/s
Explanation:
Directly by conservation of momentum we can write

let x be the thrower's new velocity
(70+0.042)×2.2 + 57×0 = 70× x +0.042×35 +57×0
x = 2.18032m/s
so the velocity of 70 kg man = 2.18032m/s
so throwers new velocity = 2.18032m/s
now again by conservation of momentum
0.042×35 = (57+0.042) ×y
y = 0.02577m/s
so catchers new velocity = 0.02577m/s
Answer:
Fm is the net force down on the metal in air
Fm / 2 is the net force down on the metal in liquid
Fl is the buoyant force on the metal due to liquid
Fm - Fl = Fm / 2 equating upward and downward forces
Fm / 2 = Fl
The specific gravity of the metal is twice that of the liquid
Note: F = M g = ρ V g since ρ = M / V