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Kisachek [45]
4 years ago
10

Isopropyl methyl ether is slightly soluble with water because the oxygen atom of ethers with three or fewer carbon atoms can for

m a few hydrogen bonds with water.
(A) True
(B) False
Chemistry
1 answer:
kondaur [170]4 years ago
8 0

Answer:

True

Hydrogen bond is a partial intermolecular bonding interaction between a lone pair on an electron rich donor atom, particularly the second-row elements nitrogen (N), oxygen (O), or fluorine (F), and the antibonding orbital of a bond between hydrogen (H) and a more

electronegative atom or group. Such an interacting system is generally denoted Dn–H···Ac, where the solid line denotes a polar covalent bond, and the dotted or dashed line indicates the hydrogen bond. The use of three centered dots for the hydrogen bond is specifically recommended by the IUPAC. While hydrogen bonding has both covalence and electrostatic contributions, and the degrees to which they contribute are currently debated, the present evidence strongly implies that the primary contribution is covelant.

Hydrogen bonds can be intermolecular (occurring between separate molecules) or

intramolecular (occurring among parts of the same molecule)

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You have a solution of 600 mg of caffeine dissolved in 100 mL of water. The partition coefficient for aqueous caffeine extracted
klio [65]

Answer:

159 mg caffeine is being extracted in 60 mL dichloromethane

Explanation:

Given that:

mass of caffeine in 100 mL of water =  600 mg

Volume of the water = 100 mL

Partition co-efficient (K) = 4.6

mass of caffeine extracted = ??? (unknown)

The portion of the DCM = 60 mL

Partial co-efficient (K) = \frac{C_1}{C_2}

where; C_1= solubility of compound in the organic solvent and C_2 = solubility in aqueous water.

So; we can represent our data as:

K=(\frac{A_{(g)}}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL} )

Since one part of the portion is A and the other part is B

A+B = 60 mL

A+B = 0.60

A= 0.60 - B

4.6=(\frac{0.6-B(mg)}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL})

4.6 = \frac{(\frac{0.6-B(mg)}{60mL} )}{(\frac{B_{(mg)}}{100mL})}

4.6 × (\frac{B_{(mg)}}{100mL}) = (\frac{0.6-B(mg)}{60mL} )

4.6 B *\frac{60}{100} = 0.6 - B

2.76 B = 0.6 - B

2.76 + B = 0.6

3.76 B = 0.6

B = \frac{0.6}{3.76}

B = 0.159 g

B = 159 mg

∴ 159 mg caffeine is being extracted from the 100 mL of water containing 600 mg of caffeine with one portion of in 60 mL dichloromethane.

4 0
3 years ago
Read 2 more answers
How many moles of NaOH are in 13.25 mL of 0.323 M NaOH?
adell [148]
M=mol/L, 0.323M=mol/0.01325. Rework to solve for mol and bam! (I.e. times the two numbers)
7 0
3 years ago
Please help with the question attached<br>I need it in an hour​
lawyer [7]

Answer:

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4 0
2 years ago
The volume of a sample of <img src="https://tex.z-dn.net/?f=P_b" id="TexFormula1" title="P_b" alt="P_b" align="absmiddle" class=
murzikaleks [220]

Answer : The mass of sample is, 267.5 grams.

Explanation :

Density : It is defined as the mass of a substance contained per unit volume.

Formula used :

Density=\frac{Mass}{Volume}

Given:

Volume of Pb = 23.57cm^3

Density of Pb = 11.35g/cm^3

Now put all the given values in the above formula, we get the mass of Pb.

11.35g/cm^3=\frac{Mass}{23.57cm^3}

Mass=267.5195g=267.5g

Therefore, the mass of sample is, 267.5 grams.

5 0
3 years ago
Hi! I need help with this question, if it is possible, please answer immediately.
Dennis_Churaev [7]

Answer:

A.

Explanation:

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