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Elis [28]
3 years ago
7

It is 12:00 and you just heard that local officials are tracking a violent storm heading westward, directly for your town and sc

hool. The storm is traveling at 25 km/hr and it is currently 75 kilometers east of your school. If the school day is not shortened, and you remain until two o’clock (the official end of the day), will you and all others in the school get home before the storm hits?
Chemistry
2 answers:
Softa [21]3 years ago
6 0

Answer:

Yes.

Explanation:

i got it correct :)

strojnjashka [21]3 years ago
3 0

Answer:

The answer is : Yes

Explanation:

because it 12:00 and the storm is moving at 25km/hr and it 75 km away that means in three hours the storm would hit your town so at 3:00 the storm would hit at your at ends at 2:00 so yes you would get home before he storm hit.

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How much greater is the pressure at the deepest part of the ocean compared to that found at sea level?
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What substance is oxidized in the following reaction? 4HCl + MnO2 → Cl2 + 2H2O + MnCl2
Blizzard [7]

Answer:

Cl⁻ was oxidized.

Explanation:

  • 4HCl + MnO₂ → Cl₂ + 2H₂O + MnCl₂

Oxidation can be defined as the process in which the oxidation number of a substance increases.

On the left side of the equation, Cl has a charge of -1 (in HCl); while on the right side of the equation Cl has a charge of 0 in Cl₂.

Thus, Cl⁻ was oxidized.

8 0
3 years ago
The solubility of oxygen in lakes high in the Rocky Mountains is affected by the altitude. If the solubility of O2 from the air
IceJOKER [234]

Answer:

1.75\cdot 10^{-4} M

Explanation:

Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:

S = k_H p^o

Where k_H is Henry's law constant.

Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.

Given initially:

S_1 = 2.67\cdot 10^{-4} M

Also, at sea level, we have an atmospheric pressure of:

p = 1.00 atm

Given mole fraction:

\chi_{O_2} = 0.209

According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:

p^o = \chi_{O_2} p

Then the equation becomes:

S_1 = k_H \chi_{O_2} p

Solve for k_H:

k_H = \frac{S_1}{\chi_{O_2} p} = \frac{2.67\cdot 10^{-4} M}{0.209\cdot 1.00 atm} = 0.001278 M/atm

Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:

p = 0.657 atm

Apply Henry's law using the constant we found:

S_2 = k_H \chi_{O_2} p = 0.001278 M/atm\cdot 0.209\cdot 0.657 atm = 1.75\cdot 10^{-4} M

8 0
3 years ago
What mass of aluminum chloride could be made from 8.1 g of aluminum and 4.2 L of chlorine at STP?
posledela
In this problem Al metal is a limiting reactant as it is present in less amount as compared to chlorine gas, Hence, controls the formation of ALCl3. So, the amount of AlCl3 produced is 40.05 grams. Solution is as follow,

3 0
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