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3 years ago

Which atomic model proposed that electrons move in specific orbits the nucleus of an atom?

Chemistry

1 answer:

MrRa [10]3 years ago

3 0

Bohr's atomic model proposed that electrons move in specific orbits around the nucleus of an atom.

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1.20×10−8s to nanoseconds

AveGali [126]

Answer:

There are 12 nanoseconds in $1.2\times 10^{-8}\ s$ .

Explanation:

We need to convert $1.2\times 10^{-8}\ s$ to nanoseconds.

We know that,

$1\ s=10^9\ ns$

Now using unitary method to solve it such that,

$1.2\times 10^{-8}\ s=1.2\times 10^{-8}\ \times 10^9\\\\=1.2\times 10\\\\=12\ ns$

So, there are 12 nanoseconds in $1.2\times 10^{-8}\ s$ .

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3 years ago

When do acids follow the same naming conventions as other covalent componds

Valentin [98]

Jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjgccccccccccccccccccccc

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3 years ago

How would u describe the shape of a big drop of water. Thanks everyone for your help

Furkat [3]

Answer:

It is a semi circle with a triangle on top

6 0

3 years ago

Calcule a variação da entalpia dessa reação ( 2 NH3 (g) ---> CO(NH2)2 (s) + H2O (L) ) a partir das seguintes equações termoqu

Nitella [24]

ΔH = +438 kJ

We have three equations:

(I) N₂ + 3H₂ → 2NH₃; ΔH = -92 kJ

(II) H₂ +½O₂ → H₂O; ΔH = -286 kJ

(III) CO(NH₂)₂ + ³/₂O₂ → CO₂ + 2H₂O + N₂; ΔH = -632 kJ

From these, we must devise the target equation:

(IV) 2NH₃ + CO₂ → CO(NH₂)₂ + H₂O; ΔH = ?

_________________________________

The target equation has 2NH₃ on the left, so you reverse equation (I).

When you reverse an equation, you reverse the sign of its ΔH.

(V) 2NH₃ → N₂ + 3H₂; ΔH = +92 kJ

Equation (V) has 1N₂ on the right, and that is not in the target equation.

You need an equation with 1N₂ on the left.

Reverse Equation (III).

(VI) CO₂ + 2H₂O + N₂ → CO(NH₂)₂ + ³/₂O₂; ΔH = +632 kJ

Equation (VI) has ³/₂O₂ on the right, and that is not in the target equation.

You need ³/₂O₂ on the left.

Multiply Equation (II) by three.

When you multiply an equation by three, you multiply its ΔH by three.

(VII) 3H₂ +³/₂O₂ → 3H₂O; ΔH = -286 kJ

Now, you add equations (V), (VI), and (VII), cancelling species that appear on opposite sides of the reaction arrows.

When you add equations, you add their ΔH values.

_______________________________________

We get the target equation (IV):

(V) 2NH₃ → N₂ + 3H₂; ΔH = + 92 kJ

(VI) CO₂ + 2H₂O + N₂ → CO(NH₂)₂ + ³/₂O₂; ΔH = +632 kJ

(VII) 3H₂ +³/₂O₂ → 3H₂O; ΔH = -286 kJ

(IV) 2NH₃ + CO₂ → CO(NH₂)₂ + H₂O; ΔH = +438 kJ

7 0

3 years ago

you have an object with mass of 86 g and volume of 10 cm^3 (cubed). calculate density, show your work, and identify which materi

sleet_krkn [62]

Answer:

8.6g/cm³ (BRASS)

Explanation:

Given the following :

Mass of object = 86g

Volume of object = 10cm³

The density of an object is calculated using the formula :

Density(g/cm³) = mass(g) / volume(cm³)

Inputting our values :

Density = 86g / 10cm³

Density = 8.6g/cm³

According to the table provided, the object which corresponds to having a density of 8.6g/cm³ is BRASS

6 0

3 years ago

Which atomic model proposed that electrons move in specific orbits the nucleus of an atom?​

Which atomic model proposed that electrons move in specific orbits the nucleus of an atom?