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hodyreva [135]
3 years ago
9

Determine the oxidation number of sulfur in S203 ( with steps)

Chemistry
1 answer:
sdas [7]3 years ago
8 0

Answer:

The oxidation number of sulphur in is +2

Explanation:

<em>S</em><em>2</em><em>O</em><em>3</em><em> </em><em>2</em><em>-</em>

<em>2</em><em> </em><em>(</em><em>S</em><em>)</em><em> </em><em>+</em><em> </em><em>3</em><em>(</em><em>O</em><em>)</em><em>=</em><em>-</em><em>2</em>

<em>2</em><em> </em><em>(</em><em>S</em><em>)</em><em> </em><em>+</em><em> </em><em>3</em><em>(</em><em>-</em><em>2</em><em>)</em><em>=</em><em>-</em><em>2</em>

<em>2</em><em> </em><em>(</em><em>S</em><em>)</em><em> </em><em>+</em><em> </em><em>(</em><em>-</em><em>6</em><em>)</em><em> </em><em>=</em><em>-</em><em>2</em>

<em>2</em><em> </em><em>S</em><em> </em><em>=</em><em> </em><em>+</em><em>4</em>

<em>S</em><em>=</em><em> </em><em>+</em><em /><em>2</em><em />

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