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3 years ago

Why do you Think you weight less on Uranus than earth even though it is more massive planet ?

Chemistry

1 answer:

Phantasy [73]3 years ago

7 0

Answer:

You would weigh less on Uranus than on Earth because Uranus is far less mass-ive and dense than the Earth. This means that there is less gravity. Therefore, you would weigh less.

Explanation:

Even though Uranus is bigger, it is less massive; that is, there is less mass that makes up the planet. The volume of the planet might be larger, but the actual amount of mass isn't.

By the way, you couldn't stand on Uranus. It's made of gas!

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After 11.5 days, 12.5% of a sample of radon-222 that originally weighed 42g remains. What is the half-life of this isotope?

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Half-life is defined as the amount of time it takes a given quantity to decrease to half of its initial value. The equation to describe the decay is
Nt=N0(1/2) $^{t/t(1/2)}$ where N0 is the initial quantity, Nt is the remaining quantity after time t, t1/2 is the half-time. So work out the equation, t1/2 = t (-ln2)/ln(Nt/N0) = 11.5*(-ln2)/ln(12.5/100) = 3.83 days

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3 years ago

A decorative "ice" sculpture is carved from dry ice (solid CO2) and held at its sublimation point of –78.5°C. Consider the proce

Leno4ka [110]

Answer:

The answers to the questions are;

a. The entropy of sublimation for carbon dioxide (the system) is

134.07 J/Kmol.

b. The entropy of the universe for this reversible process is 376 J/K.

Explanation:

Entropy of sublimation is the entropy change experienced following the transformation of a mole of solid to vapor at the temperature where the sublimation is taking place

a. We note that the mass of the solid CO₂ = 389 g

Molar mass of CO₂ = 44.01 g/mol

Number of moles of CO₂ in the sculpture = Mass/(Molar mass)

= (389 g)/(44.01 g/mol) = 8.84 Moles

Entropy of sublimation is given by

ΔS $_{sublimation}$ = $S_{vapor}$ - S $_{solid}$ = $\frac{\Delta H_{sublimation}}{T}$

Where:

ΔH $_{sublimation}$ = 26.1 KJ/mol

T = Temperature = –78.5°C = ‪194.65‬ K

Therefore the amount of heat required to cause the 389 g of dry ice to sublime = 26.1 KJ/mol × 8.84 Moles = 230.695 KJ

Therefore the entropy of sublimation = ΔS $_{sublimation}$ = $\frac{230.695 KJ}{194.65 K}$

= 1.185 KJ/K

= 1185 J/K = 1185/8.84 J/Kmol = 134.07 J/Kmol

b. The entropy of the universe is given by;

ΔS $_{universe}$ = $\Delta S_{system}$ + ΔS $_{surrounding}$

If the heat absorbed by the system is the same as the heat given off by the surrounding, then we have;

ΔS $_{universe}$ = $\frac{Q}{ T_{system}}$ $-\frac{Q}{T_{surrounding}}$

=1.185 KJ/K - $-\frac{230.695 KJ}{285.15K}$ = 1.185 KJ/K - 0.809 KJ/K = 0.376 KJ/K

= 376 J/K.

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3 years ago

When the free-energy change (AG) of a reaction is negative, the reaction is said to be: Endergonic Non spontaneous Spontaneous E

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Answer:

Spontaneous

Explanation:

For a spontaneous reaction , the value for the change in free energy or gibbs' free energy is negative .

The change in free energy , i.e. , ΔG , denotes the maximum amount of usable energy released , as going from initial state , i.e. , the reactant towards the final state , i.e. , the product .

And , the sign of the ΔG , determines whether the reaction is Spontaneous or non Spontaneous or at equilibrium ,

i.e. ,

ΔG < 0 , the reaction is Spontaneous

ΔG > 0 , the reaction is non Spontaneous

ΔG = 0 , the reaction is at equilibrium

For ,

ΔG < 0 , that the reaction proceed without any energy input , hence , it is Spontaneous in nature .

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3 years ago

Why do you Think you weight less on Uranus than earth even though it is more massive planet ? ￼￼

Why do you Think you weight less on Uranus than earth even though it is more massive planet ?