Answer:
<h2>
<em><u><</u></em><em><u>1</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u><</u></em><em><u>7</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u><</u></em><em><u>2</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u><</u></em><em><u>8</u></em></h2><h3>
<em><u>or</u></em></h3><h2>
<em><u><</u></em><em><u>4</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u><</u></em><em><u>6</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u><</u></em><em><u>3</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u><</u></em><em><u>5</u></em></h2>
Step-by-step explanation:
<h3>
<em><u>There</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>totally</u></em><em><u> </u></em><em><u>four</u></em><em><u> </u></em><em><u>pairs</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>alternate</u></em><em><u> </u></em><em><u>angles</u></em><em><u>:</u></em></h3>
<em><u>Alternate</u></em><em><u> </u></em><em><u>interior</u></em><em><u> </u></em><em><u>angles</u></em><em><u>:</u></em><em><u>-</u></em>
<em>Pairs</em><em> </em><em>-</em><em> </em><2 and <8 ; <3 and <5
<em><u>Alternate</u></em><em><u> </u></em><em><u>exterior</u></em><em><u> </u></em><em><u>angles</u></em><em><u>:</u></em><em><u>-</u></em>
<em>Pairs</em><em> </em><em>-</em><em> </em><1 and <7 ; <4 and <6
<h3>{
<em><u>You</u></em><em><u> </u></em><em><u>can</u></em><em><u> </u></em><em><u>choose</u></em><em><u> </u></em><em><u>any</u></em><em><u> </u></em><em><u>two</u></em><em><u> </u></em><em><u>pair</u></em><em><u>}</u></em></h3>
Answer:
Step-by-step explanation:
Answer:
- 20.3% o P=0.203
- 88.8% or P=0.888
- 18% or P=0.18
- 78% or P=0.78
8Step-by-step explanation:
- The probability is 188 wich are favorable cases for a fan attending multiple games over 925 wich is the total cases: [tex]frac{{188}{925}}[\tex]
- If the selected fan is male we should divide the amount of multiple-game male atendees over the total amount of multiple game attendees. [tex]frac{{167}{188}}[\tex]
- We multipliply the probability of a fan being male times the probability him being multiple-game male atendee [tex]frac{{700}{925}}frac{{167}{700}}[\tex]
- This probabily es the sum of the probability of an fan being man plus the prob of having attended multiple games, minus the probability of being a man AND having attended multiple games (as to not account for them twice) [tex]frac{{700}{925}}+frac{{188}{700}}-0.18[\tex]
Answer:
#9 is 3
#19 0.56
#20 0.63 :)
Step-by-step explanation:
Since the volume of a cube is S^3, where S is the length of one of the sides, we take the cube root of 1000 and get the edge length of the cube is 10 inches.