What do the spheres in this model represent?

A bus initially moving at 20 m/s with an acceleration of -4m/s² for 5

Alborosie

Answer:

50m; 0m/s.

Explanation:

Given the following data;

Initial velocity = 20m/s

Acceleration, a = - 4m/s²

Time, t = 5secs

To find the displacement, we would use the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Substituting into the equation, we have;

$S =20*5 + \frac{1}{2}*(-4)*5^{2}$

$S =100 + (-2)*25$

$S =100 - 50$

S = 50m

Next, to find the final velocity, we would use the third equation of motion;

$V^{2} = U^{2} + 2aS$

Where;

V represents the final velocity measured in meter per seconds.

U represents the initial velocity measured in meter per seconds.

a represents acceleration measured in meters per seconds square.

<em>Substituting into the equation, we have;</em>

$V^{2} = 20^{2} + 2(-4)*50$

$V^{2} = 400 - 400$

$V^{2} = 0$

V = 0m/s

<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>

5 0

3 years ago

The velocity of sound in air at 300C is approximately :

kumpel [21]

The velocity of sound in at 300C is 511.3 m/s.

Explanation:

The equation that gives the speed of sound in ar as a function of the air temperature is the following:

$v=(331.3+0.6T) m/s$

where

T is the temperature of the air, measured in Celsius degrees

In this problem, we want to find the speed of sound in ar for a temperature of

$T=300^{\circ}C$

Substituting into the equation, we find:

$v=331.3 + 0.6(300)=511.3 m/s$

So, the velocity of sound in at 300C is 511.3 m/s.

Learn more about sound waves:

brainly.com/question/4899681

#LearnwithBrainly

6 0

3 years ago

An unstrained horizontal spring has a length of 0.39 m and a spring constant of 350 N/m. Two small charged objects are attached

Vera_Pavlovna [14]

Answer:

A) The possible algebraic signs will either be both positive (+) or both negative (-) charged since the 2 objects are repelling each other to stretch the string.

B) Magnitude of charges = 1.206 × 10^(-6) C

Explanation:

We are given;

Spring constant;k = 350 N/m

Spring length;L = 0.39 m

Stretched length of spring;x = 0.022 m

A) The spring stretches by 0.022m. Therefore, the total force is (350 × 0.022) N = 7.7N. The charged objects will either be both positive (+) or both negative (-) charged since they are repelling each other to stretch the string.

B) Force (F) required to stretch spring is given by the formula;

F = kx

Thus:

F = (350 × 0.022)

F = 7.7 N

Now, if we assume point charges, then the distance (r) between them will be given as:

r = (0.39 + 0.022) = 0.412 m

Coulomb's Law has a formula:

F = k(q1×q2)/r²

where k is coulomb's constant = 8.99 × 10^(9) Nm²/C²

Making q1 × q2 the subject, we have;

(q1 × q2) = Fr²/k = 7.7 × 0.412²/(8.99 × 10^(9))

(q1 × q2) = 14.54 × 10^(-11) C

We are told that both charges are equal, thus; |q1| = |q2|

So;

q = √(14.54 × 10^(-11)) = 1.206 × 10^(-6) C

6 0

3 years ago

State the equation of momentum impulse theorem.

Paladinen [302]

Answer:

J = Δp

Explanation:

The impulse-momentum theorem says that the impulse J is equal to the change in momentum p.

J = Δp

3 0

3 years ago

Explain what is happening when roller coaster is at each point. **The roller coaster has started at A and goes to D.

yaroslaw [1]

Answer:

At point A, the cart has high potential energy. At point b, the cart is pulled down by gravity. At point c, the cart gains its highest kinetic energy. At point d, the cart returns back to the same state but with lower potential energy.

3 0

2 years ago