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sattari [20]
3 years ago
5

If the electric field between the plates has a magnitude of 1.4×105 V/m , what is the potential difference between the plates?

Physics
1 answer:
Bogdan [553]3 years ago
5 0

Answer: V = Ed

V = 107.8 Volts

The distance between plate is missing, below is a possible complete question:

A Parallel-plate Capacitor Has Plates Separated By 0.77 Mm,If the electric field between the plates has a magnitude of 1.4×105 V/m , what is the potential difference between the plates?

Explanation:

Potential difference V = electric field E × distance d

V = Ed

E = 1.4 × 10^5 V/m

d = 0.77mm = 0.77 × 10^-3 m

V = 1.4 × 0.77 × 10^(5-3) Volt

V = 1.078 × 10^2 Volts

V = 107.8 Volts

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Which of the following choices correctly identifies the process created by moving a magnet through a conducting loop?
jolli1 [7]

Answer: D.) electromagnetic induction

Explanation: Electroctromagnetic induction may be explained as a process whereby electric current is induced or produced by difference in potential resulting from the movement of conductor across a magnetic field.

In simple terms, an electromotive force is induced when a magnet is moved through a conducting loop.

The electromotive force produced by moving a magnet through a conducting loop can be represented by the relation:

E = - N (dΦ / dt)

Where E = electromotive force in voltage

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dt = change in time

3 0
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What is the charge of the negative sphere
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Answer:

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8 0
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Calculate the pressure on a man’s foot when a woman who weighs 520 N steps on his foot with her heel which has an area of 0.001
Vinvika [58]

Answer:

520000  or 520000 pa

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6 0
3 years ago
How many carbon-14 atoms are left after 1 half-life
Marizza181 [45]

Answer:

The time it takes for 14C to radioactively decay is described by its half-life. C has a half-life of 5,730 years. In other words, after 5,730 years, only half of the original amount of 14C remains in a sample of organic material. After an additional 5,730 years–or 11,460 years total–only a quarter of the 14C remains.

Explanation:

Hope this helps

7 0
2 years ago
You collect some more data on that horse at a later time interval, but now you are measuring thehorse’s velocity, not its positi
Monica [59]

Answer:

a)  x(t) = 10t + (2/3)*t^3

b) x*(0.1875) = 10.18 m

Explanation:

Note: The position of the horse is x = 2m. There is a typing error in the question. Otherwise, The solution to cubic equation holds a negative value of time t.

Given:

- v(t) = 10 + 2*t^2 (radar gun)

- x*(t) = 10 + 5t^2 + 3t^3  (our coordinate)

Find:

-The position x of horse as a function of time t in radar system.

-The position of the horse at x = 2m in our coordinate system

Solution:

- The position of horse according to radar gun:

                              v(t) = dx / dt = 10 + 2*t^2

- Separate variables:

                              dx = (10 + 2*t^2).dt

- Integrate over interval x = 0 @ t= 0

                             x(t) = 10t + (2/3)*t^3

- time @ x = 2 :

                              2 = 10t + (2/3)*t^3

                              0 = 10t + (2/3)*t^3 + 2

- solve for t:

                              t = 0.1875 s

- Evaluate x* at t = 0.1875 s

                              x*(0.1875) = 10 + 5(0.1875)^2 + 3(0.1875)^3

                              x*(0.1875) = 10.18 m

3 0
3 years ago
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