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3 years ago

If the electric field between the plates has a magnitude of 1.4×105 V/m , what is the potential difference between the plates?

Physics

1 answer:

Bogdan [553]3 years ago

5 0

Answer: V = Ed

V = 107.8 Volts

The distance between plate is missing, below is a possible complete question:

A Parallel-plate Capacitor Has Plates Separated By 0.77 Mm,If the electric field between the plates has a magnitude of 1.4×105 V/m , what is the potential difference between the plates?

Explanation:

Potential difference V = electric field E × distance d

V = Ed

E = 1.4 × 10^5 V/m

d = 0.77mm = 0.77 × 10^-3 m

V = 1.4 × 0.77 × 10^(5-3) Volt

V = 1.078 × 10^2 Volts

V = 107.8 Volts

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3 years ago

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Answer:

7.82 s

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2 years ago

A stationary police car emits a sound of frequency 1240 HzHz that bounces off of a car on the highway and returns with a frequen

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Answer

given,

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Using Doppler's effect formula

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v is the speed of the car

Frequency of the police car received

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now, inserting the value of equation (1)

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3 years ago

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2 years ago

A person can see clearly up close but cannot focus on objects beyond 75.0 cm. She opts for contact lenses to correct her vision.

Pavel [41]

Answer:

(a) nearsighted

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2 years ago