The work-done by the wind as the bug undergoes the displacement is 80 J.
The given parameters;
- Mass of the bug, m = 45 g
- Force exerted, F = (4.0 î – 6.0j) x 10⁻² N
- Displacement of the bug, r = (8.0î - 8.0j) m
The work-done by the wind as the bug undergoes the displacement is obtained by finding the dot product of the force and the displacement;
Work done = F. r
Work done = (4.0 î – 6.0j) x 10⁻² . (8.0î - 8.0j)
Work done = (32i²) + (48j²)
Work done = 32(1) + 48(1)
Work done = 80 J.
Thus, the work-done by the wind as the bug undergoes the displacement is 80 J.
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Answer:
T₂ = 305.17 K
Explanation:
Given that,
Heat, Q = 6000 J
Mass, m = 200 gram
Initial temperature, T₁ = 25° C
We need to find its final temperature. Let it is T₂.
We know that,
Where
c is the specific heat of water, c = 4.18 J/g°C
So,
So, the final temperature is equal to 305.17 K.
Between 2 weeks and a month
Answer:
25.8 lb/in²
Explanation:
Gay-Lussac's law tells us that given an ideal gas of a certain mass has a constant volume, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.
Answer:
the kinetic energy decreases and the potential energy Increases.
Explanation:
as the comet travels away from the star it gains an energy which it posses because of its position or state.once the comet moves away form the star the kinetic decreases until its lost all together to where the potential energy starts increasing.
