Answer:
I for a rod about its center is I = M L^2 / 12
A = L (1/2 - 1/3) = L / 6 distance from middle to location L/3
A^2 = L^2 / 36
I = M L^2 (1/12 + 1/36) = M L^2 (4 / 36) = M L^2 / 9
I about given location by parallel axis theorem
Answer:
a) 4.9 s
b) 167.8 m
Explanation:
Hello!
To solve this question we need to make use of the equations of motion of both the motorcycle xm(t) and the car xc(t) at t=5
Let us consider the position of the motorcycle at t=5 as the origin, that is:
xm(t+5) = vt + (1/2)at^2
xc(t+5) = vt + 60 m
where v = 22.0m/s and a=5m/s^2
We are looking for the time t' when the position of the car and the motorcycle are the same:
xm(t'+5)=xc(t'+5)
vt' + (1/2)at'^2 = vt' +60m
t' = √(120 m /a) = 4.89898... s
Since we are considering the origin of the cooordinate system at the position when the motorcycle starts to accelerate, the distance travelled by the motorcycle until it catches the car is given by:
xm(t'+5)= vt' + (1/2)at'^2
xm(9.89898s) = (22 * 9.89898 + 2.5 * 9.89898^2)m
xm(9.89898s)= 167.777... m
To act as the Sun' was accepted but if you put 'sunlight' alone it was not accepted. The examiner wanted you to state that the infra red radiation was needed to warm up the water.
Answer:
57m
Explanation:
speed = 5.7m/s
or 57/10 m/s
so definitely the time taken will be 10 secs
so speed = distance/time taken
5.7= distance/10
distance = 5.7× 10
Distance = 57m
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