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Tresset [83]
3 years ago
12

Coming to the bottom of a mountain, a skier moving with speed v collides with a barrier and is brought to a stop in an amount of

time t. Over the course of the impact, the skier experienced an average net force F from the barrier. If the skier\'s initial velocity had been the same (v), but the time of impact to come to a full stop had been four times as long (4t), what would have been the average net force exerted on the skier during the collision? The average net force would have been...a) F/4b)Fc)4Fd) F/2e)2FIf the time of impact to come to a full stop had been the same (t), but the skier\'s initial velocity had been half as much (v / 2), what would have been the average net force exerted on the skier during the collision? The average net force would have been...a) 4Fb)Fc)2Fd) F/4e)F/2
Physics
1 answer:
IRISSAK [1]3 years ago
8 0

Answer:

Explanation:

Impulse of a force is measured by force x time or F X t

Impulse also equals change in momentum or

F x t = m v₂ - m v₁

The given case is as follows

in the first case

F x t = mv - o = mv

F = mv / t

in the second case

F₁ x 4 t = mv

F₁ = 1/4 x mv /t

F₁ = F / 4

option a) is correct .

iii )

In the last case

F₂ X t = m v/2 -0

F₂ = 1/2 x mv / t

= 1/2 x F

F₂ = F/2

Option e ) is correct.

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If a light bulb is missing or broken in a parallel circuit, will the other light bulb right ?
Nataly [62]

No because the path the electricity needs to follow is broken. In parallel circuit,electricity has more that one path to follow.
7 0
3 years ago
Suppose you want to represent the velocity of a BALL with respect to a particular frame of reference from aboard a moving TRAIN.
tatyana61 [14]

Answer:

Explanation:

We would most likely write the velocity of the ball as follow :

V(b<em>all</em> with respect to t<em>rain)</em> = Vbt

4 0
3 years ago
A frictionless spring with a 4-kg mass can be held stretched 0.2 meters beyond its natural length by a force of 30 newtons. If t
maxonik [38]

Answer:

The position for mass is x(t)=36.75sin(37.5t)

Explanation:

Let x(t) donate the position of mass at time t,Then x satisfies the differential equation

m\frac{d^2x}{dt^2} +kx=0\\here\\m=4kg\\k=30N/0.2m\\thus\\w^2=k/m=30N/0.2m*4kg=37.5

The general solution is

(x)t=C_{1}cos(37 .5t)+C_{2}sin(37.5t)

It follows

x'(t)=-37.5C_{1}sin(37.5t)+37.5C_{2}cos(37.5t)\\now\\x(0)=0\\gives\\C_{1}=0\\ and\\x'(0)=1m/s\\gives\\C_{2} =36.75

thus the position of mass is

x(t)=36.75sin(37.5t)

7 0
3 years ago
How do you determine true displacement value of an object that has moved?
WITCHER [35]
Diceplacement is the distance an object has traveled in a certain direction
for example, if you were to walk North for 20m, then east for 40m, the <u>distance</u> you have traveled is 60m however your displacement is the distance between your starting position and your end position;
sqrt(20^2+40^2) = 44.7m
and because displacement is a vector, there needs to be a direction;
sin(theta)=40/44.7
theta=63.4 degrees East of North

therefore the true displacement is 44.7m at 63.4 degrees East of North
3 0
3 years ago
A 2.7 kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0-m-high cliff. At the instant the ball i
madam [21]

Answer:

(a) At what angle above the horizontal should the ball be thrown so that the runner will catch it  just before it hits the ground? (b) How far does the woman run before she catches the ball?

(a) = 72.54°

   ≅ 72.5°

(b) = 33.4 m

Explanation:

see the attached file below

4 0
3 years ago
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