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Tresset [83]
3 years ago
12

Coming to the bottom of a mountain, a skier moving with speed v collides with a barrier and is brought to a stop in an amount of

time t. Over the course of the impact, the skier experienced an average net force F from the barrier. If the skier\'s initial velocity had been the same (v), but the time of impact to come to a full stop had been four times as long (4t), what would have been the average net force exerted on the skier during the collision? The average net force would have been...a) F/4b)Fc)4Fd) F/2e)2FIf the time of impact to come to a full stop had been the same (t), but the skier\'s initial velocity had been half as much (v / 2), what would have been the average net force exerted on the skier during the collision? The average net force would have been...a) 4Fb)Fc)2Fd) F/4e)F/2
Physics
1 answer:
IRISSAK [1]3 years ago
8 0

Answer:

Explanation:

Impulse of a force is measured by force x time or F X t

Impulse also equals change in momentum or

F x t = m v₂ - m v₁

The given case is as follows

in the first case

F x t = mv - o = mv

F = mv / t

in the second case

F₁ x 4 t = mv

F₁ = 1/4 x mv /t

F₁ = F / 4

option a) is correct .

iii )

In the last case

F₂ X t = m v/2 -0

F₂ = 1/2 x mv / t

= 1/2 x F

F₂ = F/2

Option e ) is correct.

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Which of the following statements best explains why elements in the same family of the periodic table have similar bonding prope
slava [35]

Answer: D. The elements have the same number of valence electrons

Explanation: The chemical reactivity of elements is governed by the valence electrons present in the element.

The elements present in the same group or vertical column have similar valence configurations and thus behave similarly in chemical reactions or have similar bonding properties.

For Example: Both fluorine and chlorine belong to same family or group and both have 7 electrons in their valence shell and thus accept single electron to attain noble gas configuration.

F:9:1s^22s^22p^5

F^-:10: 1s^22s^22p^6

Cl:17:1s^22s^22p^63s^23p^5

Cl^-:18:1s^22s^22p^63s^23p^6

thus both would bond with a cation bearing a single positive charge.

3 0
3 years ago
A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0 degrees. What is
soldier1979 [14.2K]
W =F triangle d cosine0. F = 25 Newton’s. Delta d = 50 meters. Theta =40.0 degrees
3 0
4 years ago
A person travels by car from one city to another with different constant speeds between pair of cities. She drives for 36 min at
Softa [21]

 Change minutes to hrs, divide by 60:
30 min = .50 hrs
45 min = .75 hrs
12 min = .20 hrs
----------------
total + 1.45 hrs, total travel time
:

let a = average speed for the trip
:
Write a dist equation, dist = speed * time
:
80(.5) + 100(.20) + 40(.75) = 1.45a
40 + 20 + 30 = 1.45a
90 = 1.45a
a =
a = 62.069 km/h, for the entire trip
and
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3 0
3 years ago
The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou
puteri [66]

Answer:

t=5.3687\ s  is the time taken by the car to accelerate the desired range of the speed from zero at full power.

Explanation:

Given:

Range of speed during which constant power is supplied to the wheels by the car is 0\ mph\ to\ 70\ mph.

  • Initial velocity of the car, v_i=0\ mph
  • final velocity of the car during the test, v_f=32\ mph=14.3052\ m.s^{-1}
  • Time taken to accelerate form zero to 32 mph at full power, t=1.2\ s
  • initial velocity of the car, u_i=0\ mph
  • final desired velocity of the car, u_f=64\ mph=28.6105\ m.s^{-1}

Now the acceleration of the car:

a=\frac{v_f-v_i}{t}

a=\frac{14.3052-0}{1.2}

a=11.921\ m.s^{-1}

Now using the equation of motion:

u_f=u_i+a.t

64=0+11.921\times t

t=5.3687\ s is the time taken by the car to accelerate the desired range of the speed from zero at full power.

8 0
3 years ago
Help and explain thanks
ludmilkaskok [199]

Answer:

the faster an object moves the more kinetic it has. the more mass an object has, the more kinetic energy it has.

4 0
2 years ago
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