Un acróbata de 60.0 kg está unido a un cordón de bungee con un resorte de 10.0 m de longitud . Salta de un puente que abarca un
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Hi there!
We can begin by finding the acceleration of the block.
Use the kinematic equation:
The block starts from rest, so:
Now, we can do a summation of forces of the block using Newton's Second Law:
mb = mass of the block
T = tension of string
Solve for tension:
Now, we can do a summation of torques for the wheel:
Rewrite:
We solved that the linear acceleration is 1.5 m/s², so we can solve for the angular acceleration using the following:
Now, plug in the values into the equation:
Answer:
C = 1.01
Explanation:
Given that,
Mass, m = 75 kg
The terminal velocity of the mass,
Area of cross section,
We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,
Weight of the object = drag force
R = W
or
Where
is the density of air = 1.225 kg/m³
C is drag coefficient
So,
So, the drag coefficient is 1.01.