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vaieri [72.5K]
2 years ago
5

Un acróbata de 60.0 kg está unido a un cordón de bungee con un resorte de 10.0 m de longitud . Salta de un puente que abarca un

río desde una altura de 50.0 m. Cuando finalmente se detiene, el cordón tiene una longitud estirada de 30.0 m. Trata el acrobata como una masa puntual, y no tener en cuenta el peso de la cuerda de bungee. Asumiendo que la constante de resorte del bungee es de 80.3 N/m, cual es el total de energía potencial en relación con el agua cuando el hombre deja de caer? *
Physics
1 answer:
Ede4ka [16]2 years ago
8 0

Answer:

What kind of languege is this please?

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den301095 [7]

Answer:

68 m

Explanation:

Given that the horizontal velocity of the birdman = 17 m/s and

the height, h= 78 m.

The gravitational force is acting in the downward direction, so it will not change the horizontal speed.

The horizontal speed will remains be constant and will be equal to the initial horizontal speed of the turd.

Initially, the turd was also flying horizontally with the birdman, so the initial velocity of the turd is the same as the horizontal velocity of the birdman, i.e In the horizontal direction, u_0=17 m/s.

In the vertical direction, u = 0,

The distance to be traveled, in the direction of application of force, is equals to the height of the turd, i.e

s= 78 m

Let t be the time taken to cover a distance of 78 m.

Now, applying the equation of motion in the vertical direction,

s=ut+\frac 12 at^2

where u is the initial velocity and a is the acceleration due to gravity in the direction of displacement,s.

Here, a=g=9.81 m/s^2, so

78=0\times t +\frac 12 (9.81)t^2

\Rightarrow t^2=(78\times2)/9.81

\Rightarrow t = 4 seconds.

Hence, the time taken to reach the ground is 4 seconds.

As the horizontal speed, u_0=17 m/s, is constant throughout the journey, so

the horizontal distance covered by turd

= u\times t

= 17 \times 4 = 68 m.

So, the distance of landing from the start of the field is 68 m as the birdman releases a turd directly  above the start of the field.

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5 0
3 years ago
A 0.2 kg hockey puck moving at 80 m/s is caught by a 40 kg goalie at rest. With what speed does the goalie slide on the slide?
Lady_Fox [76]

Answer:

V = 0.39 m/s

Explanation:

Given that,

Mass of hockey puck, m = 0.2 kg

Mass of goalie = 40 kg

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We need to find the speed with which the goalie slide on the slide. Let V be the speed. Using the conservation of momentum as follows :

mv=(M+m)V\\\\V=\dfrac{mv}{M+m}\\\\V=\dfrac{0.2\times 80}{0.2+40}\\\\V=0.39\ m/s

So, the required speed is 0.39 m/s.

5 0
2 years ago
Water flows straight down from an open faucet. The cross-sectional area of the faucet is 2.4 × 10-4m2 and the speed of the water
Ksenya-84 [330]

To solve this problem it is necessary to apply the continuity equations in the fluid and the kinematic equation for the description of the displacement, velocity and acceleration.

By definition the movement of the Fluid under the terms of Speed, acceleration and displacement is,

v_2^2 = v_1^2 + 2gh

Where,

V_i = Velocity in each state

g= Gravity

h = Height

Our values are given as,

A_1 = 2.4*10^{-4} m^2

v_1 = 0.8 m/s

h = 0.11m

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v_2 = \sqrt{v_1^2 + 2gh}

v_2 = \sqrt{(0.8 m/s)^2 + 2(9.80 m/s2)(0.11 m)}

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A_2= 1.14*10^{-4} m2

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What influences the path that surface currents take?
Anastasy [175]
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Explain what it means when scientists say that the offspring of sexual reproduction are genetically diverse.
Likurg_2 [28]

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