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vaieri [72.5K]
2 years ago
5

Un acróbata de 60.0 kg está unido a un cordón de bungee con un resorte de 10.0 m de longitud . Salta de un puente que abarca un

río desde una altura de 50.0 m. Cuando finalmente se detiene, el cordón tiene una longitud estirada de 30.0 m. Trata el acrobata como una masa puntual, y no tener en cuenta el peso de la cuerda de bungee. Asumiendo que la constante de resorte del bungee es de 80.3 N/m, cual es el total de energía potencial en relación con el agua cuando el hombre deja de caer? *
Physics
1 answer:
Ede4ka [16]2 years ago
8 0

Answer:

What kind of languege is this please?

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A car engine burns fuel and has moving parts. Sometimes, an engine can become too hot and overheat. What can prevent the engine
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Read 2 more answers
The distribution of total body protein in healthy adult men is approximately Normal, with mean 12.3 kg and standard deviation 0.
Sophie [7]

Answer:

P(12.25\leq x \leq 12.35 ) = 0.9876

Explanation:

given,

mean (μ) = 12.3 Kg

standard deviation (σ ) = 0.1

random sample = 25

probability between 12.25 and 12.35 kg

P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{\sqrt{n}}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{\sqrt{n}}}\leq z)

P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{\sqrt{25}}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{\sqrt{25}}}\leq z)

P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{5}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{5}}\leq z)

P(12.25\leq x \leq 12.35 ) = P(\dfrac{5 (12.35-12.3)}{0.1}\leq z)- P(\dfrac{5(12.25-12.3)}{0.1}\leq z)

P(12.25\leq x \leq 12.35 ) = P(\dfrac{2.5\leq z)- P(-2.5\leq z)

using z-table

P(12.25\leq x \leq 12.35 ) = 0.9938 - 0.0062

P(12.25\leq x \leq 12.35 ) = 0.9876

4 0
3 years ago
A motor-cycle rider going 90km/hr around a curve with a radius of 100m must lean at an angle to the vertical. The angle at which
BartSMP [9]

Answer:

The angle of inclination of the rider to the vertical is 32.5⁰.

Explanation:

Given;

linear speed of the motor cycle, v = 90 km/hr = 25 m/s

radius of the circle, r = 100 m

The angle of inclination of the rider to the vertical is calculated using banking angle formula;

\theta = tan^{-1}(\frac{v^2}{rg} )\\\\\theta = tan^{-1} (\frac{25^2}{100 \times 9.8} )\\\\\theta = 32.5 ^0

Therefore, the angle of inclination of the rider to the vertical is 32.5⁰

3 0
3 years ago
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