(A) NF3 covalent compound
(B) BaO ionic bond.
(C) NH4)2CO3 ionic bond.
(D) Sr(H2PO4)2 covalent compound
(E) IBr covalent compound
(F) Na2O ionic bond.
<h3>What are a covalent compound and ionic bond?</h3>
Covalent bonds form when two or more additional nonmetals combine. For instance, both hydrogen and oxygen are nonmetals, and when they connect to make moisture, they do so by forming covalent bonds. Combinations that are composed of only non-metals or semi-metals with non-metals will demonstrate covalent bonding and will be classified as molecular combinations.
- As a broad rule of thumb, combinations that involve a metal binding with either a non-metal or a semi-metal will show ionic bonding. Therefore, the compound created from sodium and chlorine will be ionic (a metal and a non-metal). Nitrogen monoxide (NO) will be a covalently bound molecule (two non-metals), silicon dioxide (SiO2) will be a covalently bound molecule (a semi-metal and a non-metal) and MgCl2 will be ionic (a metal and a non-metal).
- A polyatomic ion is an ion comprised of two or more particles that have a commission as a group (poly = many). The ammonium ion (see figure below) consists of one nitrogen atom and four hydrogen atoms. Concurrently, they constitute a single ion with a 1+ charge and a formula of NH4+. The carbonate ion (see figure below) consists of one carbon particle and three oxygen atoms and maintains a comprehensive charge of 2−. The procedure of the carbonate ion is CO32−.
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The atomic number is the total numbers of protons in an element
Mass is the physical property of matter can be expressed numerically in SI units.
Answer:
A
Explanation:
In this question, we are to calculate the enthalpy of change of the reaction. ΔH
To be able to do that, we use the Hess’ law and it involves the subtraction of the summed heat reaction of the reactants from that of the product.
Thus, mathematically, the enthalpy of change of the reaction would be;
[ΔH(CCl4) + 4 ΔH(HCl)] - [ΔH(CH4) + 4 ΔH(Cl2)]
We can see that we multiplied some heat change by some numbers. This is corresponding to the number of moles of that compound in question in the reaction.
Also, for diatomic gases such as chlorine in the reaction above, the heat of reaction is zero.
Thus, we can have the modified equation as follows;
[ΔH(CCl4) + 4 ΔH(HCl)] - [ΔH(CH4)]
Substituting the values we have according to the question, we have;
-95.98 + 4(-92.3) -(-17.9)
= -95.98 - 369.2 + 17.9
= -447.28 KJ/mol
