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xeze [42]
3 years ago
12

The combustion of a sample of butane, C4H10 (lighter fluid), produced 2.46 grams of water. 2 C4H10 + 13 O2 -------> 8 CO2 + 1

0 H2O (a) How many moles of water formed? (b) How many moles of butane burned? (c) How many grams of butane burned? (d) How much oxygen was used up in moles? In grams?
Chemistry
1 answer:
expeople1 [14]3 years ago
4 0
We are given with the amount of water produced in the reaction. In this case, we convert this into moles to conveniently find out other values of the compounds. In this case, a)0.1367 moles H20b)0.01367 moles butanec)0.7927 grams butaned)0.1776 moles O2 and 5.69 grams O2
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<h3>Equation :</h3>

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<h3>What is heat energy?</h3>

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1 year ago
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2 years ago
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6 0
3 years ago
In one of the routine analyses, Dr Entropy found that the concentration of phosphate had increased from 0.0090 mg/L to 0.220 mg/
wariber [46]

Answer:

The final volume should be 22 mL

Explanation:

For this problem, we will use the dilution equation:

C1*V1 = C2*V2

<u>Step 1</u>: Data given

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with V1 = the initial volume = 10 mL = 10 * 10^-3 L

with C2 = the final concentration = 0.100 mg/L

with V2 = the final volume = TO BE DETERMINED

<u>Step 2</u>: Calculating the final volume

C1*V1 = C2*V2

0.220 mg/L * 10*10^-3 L = 0.100 mg/L * V2

V2 = (0.220 mg/L * 10*10^-3 L) / 0.100 mg/L

V2 =0.022 L = 22 mL

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3 0
3 years ago
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erik [133]

Answer:

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