Answer:
See explanation below
Explanation:
This reaction is known as Ketone hydrolisis in acid medium. This involves the formation of an hemi cetal, and then, the acetal. This is often used to convert ketones or aldehydes in ethers.
The first step involves the reaction with the acid. The carbonile reacts with the acid and forms an alcohol there. The next step is the reaction of the alcohol, in this case, the methanol to form the hemi cetal. Then in the third step, we repeat the first step, using acid to turn the OH group into a great leaving group such water. Then the water leaves the molecule, leaving the space wide open in the next step for methanol, and the acetal is formed.
See picture for the curved arrow mechanism
The answer to this is C. When the wind blows its blowing the waves upward.
Explanation:
The integrated rate law for the zeroth order reaction is:
![[A]=-kt+[A]_0](https://tex.z-dn.net/?f=%5BA%5D%3D-kt%2B%5BA%5D_0)
The integrated rate law for the first order reaction is:
![[A]=[A]_0e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA%5D_0e%5E%7B-kt%7D)
The integrated rate law for the second order reaction is:
![\frac{1}{[A]}=kt+\frac{1}{[A]_0}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%3Dkt%2B%5Cfrac%7B1%7D%7B%5BA%5D_0%7D)
Where,
is the active concentration of A at time t
is the active initial concentration of A
t is the time
k is the rate constant