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3 years ago

Describe how the phases of the moon depend on the positions of the earth and the moon brainly

Chemistry

2 answers:

Brrunno [24]3 years ago

7 0

Answer:

Explanation:

The lunar phases are the changes in the shape of the illuminated part of the Moon when viewed by an observer on Earth. These changes are cyclical according to the position of the Moon respecting the Earth and the Sun. That is to say, depending on the location of the Moon, the Earth and the Sun, a greater or lesser portion of the visible face of Moon. The phases of the Moon are produced by two causes: the movement of the Moon's rotation around the Earth and because the Moon reflects the light of the Sun as a mirror.

A lunar cycle is the span of 29.5 days during which all phases are observed. At the end of the last phase, the cycle is repeated. The 4 best known forms are the new Moon, the full Moon, the waning room and the growing room, but there are other intermediate ones. Its appearance varies from 0% illumination during the new Moon to 100% when it is a full Moon.

ss7ja [257]3 years ago

5 0

The moons phases depend on how much the earth blocks light between the sun and the moon. The phases depend on where the moon is in respect to the sun in space.

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Select the statements that correctly describe the term viscosity. a.The viscosity of each substance is a constant value that wil

KatRina [158]

Answer:

D. VISCOSITY can be defined as a substance's ability to resist flow.

Explanation:

This is the statement that correctly describe the term viscosity. Viscosity explains why substances or fluids resist flow. It shows that internal friction or resistance to flow revealed by a substance. A substance with high viscosity or internal friction resist flow and one with low viscosity flow easily. Viscosity of a substance change base on various factors affecting the substance such as pressure, temperature, surface area. Substances like water has low viscosity explaining why it flows easily.

8 0

3 years ago

A molecule of glucose is comprised of 6 atoms of carbon, 12 atoms of hydrogen, and 6 atoms of oxygen.

Tcecarenko [31]

B i just did the test

5 0

2 years ago

The molarity of a solution prepared by dissolving 4.11 g of NaI in enough water to prepare 312 mL of solution is

Dimas [21]

Answer:

The correct answer is 8.79 × 10⁻² M.

Explanation:

Based on the given information, the mass of NaI given is 4.11 grams. The molecular mass of NaI is 149.89 gram per mole. The moles of NaI can be determined by using the formula,

No. of moles of NaI = Weight of NaI/ Molecular mass

= 4.11 / 149.89

= 0.027420

The vol. of the solution given is 312 ml or 0.312 L

The molarity can be determined by using the formula,

Molarity = No. of moles/ Volume of the solution in L

= 0.027420/0.312

= 0.0879 M or 8.79 × 10⁻² M

6 0

2 years ago

Identify which subatomic particles match each of these descriptions. One of the descriptions describes two particles. Make sure

Advocard [28]

Explanation:

protons have a relative charge of +1, they are located in the nucleus and the carry a positive charge

the electrons are negatively charged and have a charge of -1 . They are found orbiting on the shells .the electrons have a negligible mass of 1 / 1840

the neutrons have no charge they are located in the nucleus of an atom .

5 0

2 years ago

WILL MARK BRANILEST

ahrayia [7]

Answer:

FeCl3 is the limiting reactant

O2 is in excess

Theoretical yield Cl2 = 9.84 grams

The % yield is 96.5 %

Explanation:

Step 1: Data given

Mass of FeCl3 = 15.0 grams

Moles O2 = 4.0 moles

Mass of Cl2 produced = 9.5 grams

Step 2: The balanced equation

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

Step 3: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 15.0 grams / 162.2 g/mol

Moles FeCl3 = 0.0925 moles

Step 4: Calculate limiting reactant

FeCl3 is the limiting reactant. Because we have way more (more than ratio 3:4) moles O2 than FeCl3. It will completely be consumed (0.0925 moles). O2 is in excess. There will react = 0.069375 moles O2

There will remain 4.0 - 0.069375 = 3.930625 moles

Step 5: Calculate moles Cl2

For 4 moles FeCl3 we need 3 moles O2 to produce 2 moles Fe2O3 and 6 moles Cl2

For 0.0925 moles FeCl3 moles we'll have 6/4 * 0.0925 = 0.13875 moles Cl2.

Step 6: Calculate mass Cl2

Mass Cl2 = moles * molar mass

Mass Cl2 = 0.13875 moles * 70.9 g/mol

Mass Cl2 = 9.84 grams

Step 7: Calculate % yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (9.5 grams / 9.84 grams ) * 100%

% yield = 96.5 %

The % yield is 96.5 %

4 0

3 years ago