Describe how the phases of the moon depend on the positions of the earth and the moon brainly

Chemistry

2 answers:

Brrunno [24]3 years ago

7 0

Answer:

Explanation:

The lunar phases are the changes in the shape of the illuminated part of the Moon when viewed by an observer on Earth. These changes are cyclical according to the position of the Moon respecting the Earth and the Sun. That is to say, depending on the location of the Moon, the Earth and the Sun, a greater or lesser portion of the visible face of Moon. The phases of the Moon are produced by two causes: the movement of the Moon's rotation around the Earth and because the Moon reflects the light of the Sun as a mirror.

A lunar cycle is the span of 29.5 days during which all phases are observed. At the end of the last phase, the cycle is repeated. The 4 best known forms are the new Moon, the full Moon, the waning room and the growing room, but there are other intermediate ones. Its appearance varies from 0% illumination during the new Moon to 100% when it is a full Moon.

ss7ja [257]3 years ago

5 0

The moons phases depend on how much the earth blocks light between the sun and the moon. The phases depend on where the moon is in respect to the sun in space.

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KOH (aq) + HNO(little3) (aq) = KNO(little 3) (aq) + H20 (1)

Yuki888 [10]

The reaction already balanced

<h3>Further explanation </h3>

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:

• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product

• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1

For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:

Balancing C, H and the last O

Reaction

KOH (aq) + HNO₃ (aq) ⇒ KNO₃ (aq) + H₂0 (l)

give coefficient

aKOH (aq) + bHNO₃ (aq) ⇒ KNO₃ (aq) + cH₂0 (l)

K : left = a, right = 1⇒a=1

N : left = b, right =1, b=1

H: left = a, right a+b=2c⇒1+1=2c⇒2=2c⇒c=1

KOH (aq) + HNO₃ (aq) ⇒ KNO₃ (aq) + H₂0 (l)⇒ already balanced

5 0

3 years ago

How many phases are in a homogeneous mixture??

Mars2501 [29]

Technically there is only one phase unless you account for a solution where you have a pure liquid with something dissolved in it. Unless you count aqueous as a phase which is just dissolved. Since you are in high school the answer you are looking for is one. <span />

7 0

3 years ago

Read 2 more answers

If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 K, and then the pressure is raised

alex41 [277]

Answer:

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$