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attashe74 [19]
3 years ago
5

Physics please help someone

Physics
1 answer:
kvasek [131]3 years ago
5 0
1. You can tell what happens by looking at where the line is. The runner runs 14 meters in 4 seconds. Then for 4 seconds he rests at 14 meters from the starting point. Then the runner runs 10 meters back to 4 meters from the starting point in 5 seconds and stops.

2. To calculate the distance traveled, divide the graph into shapes by looking under the line:

We see a triangle that stops at 4 seconds, a rectangle that starts at 4 and ends at 8 seconds and finally a triangle that starts at 8 seconds and we assume that it maybe ends at 16 seconds because the graph cuts off. So now you calculate the area of these three shapes:

The area of a triangle is = bh/2 (base x height divided by 2):

The first triangle:
4 x 14/2
= 28

Now the rectangle is lw (length x width):

It doesn't matter which side is length or width so:

4 x 14 = 56

Now the third triangle which uses the same formula for the first one:

8 x 14/2
= 56

Now add all these numbers together:

28 + 56 + 56= 140m

The runner travelled 140 meters on the run.

The displacement is 4 meters north of we work with where the graph actually ends. Because the line ends for ,enters north of where the starting point is.

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Both gamma rays and x-rays are used to see inside the body. True or False
lozanna [386]

Answer:

True

Explanation:

Gamma rays and X-rays are made of packets of energy (photons) without mass or charge, with high penetrating power such that they can pass through the human body and impinge on a photographic plate creating an image of the interior of the human body. They electromagnetic radiation of high energy and high frequency that emanate from some natural sources such as cosmic sun rays and radon gas.

Gamma rays and X-rays can be man made by use of man made electronic devices and radioactive elements

Gamma rays and X-rays find use in airport security scanning and imaging services for medical testing.

8 0
3 years ago
By what factor does the sound intensity increase if the sound intensity level increases from 60 db to 61 db?
tiny-mole [99]

Answer:

\frac{I_{2}}{I_{1}} = 10^{0.1}

Explanation:

The sound intensity level β can be mathematically defined as

\beta(dB) = 10log_{10}(\frac{I}{I_{o} } )

where I_{o} is the reference intensity and is equal to 10^{-12} W/m^{2}.

Now,

\beta_{2} - \beta_{1} = 10 log\frac{I_{2} }{I_{o}} -  10 log\frac{I_{1} }{I_{o}}\\62-60= 10log(\frac{\frac{I_{2} }{I_{o} } }{\frac{I_{1} }{I_{o} } } )\\1=10log(\frac{I_{2} }{I_{1} } )\\\\\frac{I_{2} }{I_{1} }=10^{0.1}

6 0
4 years ago
A 2000 Hz siren and a civil defense official are both at rest with respect to the ground. What frequency does the official hear
astra-53 [7]

Answer:

a)f_1 = 2070.6 Hz

b)f_2 = 1929.4 Hz

Explanation:

Apparent frequency of the siren is given as

f = \frac{v_{rel}}{\lambda}

as we know that the wavelength will remain the same as it is having originally

sowe know

\lambda = \frac{340}{2000}

\lambda = 0.17 m

a) Now when wind is blowing from source to official

so we have

v_{rel} = 340 + 12 = 352 m/s

so we have

f_1 = \frac{352}{0.17}

f_1 = 2070.6 Hz

b) Now when wind is from official to source

so we have

v_{rel} = 340 - 12 = 328 m/s

so we have

f_2 = \frac{328}{0.17}

f_2 = 1929.4 Hz

4 0
4 years ago
What are the two types of magnets?
xeze [42]
Negative and positive
7 0
4 years ago
Read 2 more answers
Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1200 kg and was approaching at
GuDViN [60]

Answer:

a) v = 11.24 m / s ,    θ = 17.76º   b) Kf / K₀ = 0.4380

Explanation:

a) This is an exercise in collisions, therefore the conservation of the moment must be used

Let's define the system as formed by the two cars, therefore the forces during the crash are internal and the moment is conserved

Recall that moment is a vector quantity so it must be kept on each axis

X axis

initial moment. Before the crash

     p₀ₓ = m₁ v₁

where v₁ = -25.00 me / s

the negative sign is because it is moving west and m₁ = 900 kg

final moment. After the crash

      p_{x f}= (m₁ + m₂) vx

       p₀ₓ =  p_{x f}

       m₁ v₁ = (m₁ + m₂) vₓ

     vₓ = m1 / (m₁ + m₂) v₁

let's calculate

       vₓ = - 900 / (900 + 1200) 25

       vₓ = - 10.7 m / s

Axis y

initial moment

      p_{oy}= m₂ v₂

where v₂ = - 6.00 m / s

the sign indicates that it is moving to the South

final moment

     p_{fy}= (m₁ + m₂) v_{y}

     p_{oy} = p_{fy}

     m₂ v₂ = (m₁ + m₂) v_{y}

     v_{y} = m₂ / (m₁ + m₂) v₂

we calculate

    v_{y} = 1200 / (900+ 1200) 6

    v_{y}  = - 3,428 m / s

for the velocity module we use the Pythagorean theorem

      v = √ (vₓ² + v_{y}²)

      v = RA (10.7²2 + 3,428²2)

      v = 11.24 m / s

now let's use trigonometry to encode the angle measured in the west clockwise (negative of the x axis)

      tan θ = v_{y} / Vₓ

      θ = tan-1 v_{y} / vₓ)

      θ = tan -1 (3,428 / 10.7)

       θ = 17.76º

This angle is from the west to the south, that is, in the third quadrant.

b) To search for loss of the kinetic flow, calculate the kinetic enegy and then look for its relationship

      Kf = 1/2 (m1 + m2) v2

      K₀ = ½ m₁ v₁² + ½ m₂ v₂²

      Kf = ½ (900 + 1200) 11.24 2

      Kf = 1.3265 105 J

      K₀ = ½ 900 25²  + ½ 1200 6²

      K₀ = 2,8125 10⁵ + 2,16 10₅4

        K₀ = 3.0285 105J

the wasted energy is

        Kf / K₀ = 1.3265 105 / 3.0285 105

        Kf / K₀ = 0.4380

         

this is the fraction of kinetic energy that is conserved, transforming heat and transforming potential energy

5 0
3 years ago
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