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3 years ago

How does The centripetal fotce change if the car has less Mass?

Physics

1 answer:

vaieri [72.5K]3 years ago

5 0

Answer:

The centripetal force acting on the car is proportional to the mass of the car.

Explanation:

Let,

The mass of the car be 'm'

The velocity of the car moving in the curved path be 'v'

The radius of the curved path be 'r'

According to physics, a body moving ion circular path experience a force directed along the radius of the path. This force is called centripetal force.

The formula for centripetal force is,

F = mv²/r

Where,

a = v²/r

So, if the mass of the car changes, the centripetal force also changes proportionally according to the above equation.

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Strontium atom loses 2 electrons to become an ion.

Explanation:

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3 years ago

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The density of the metal is twice the density of liquid since acceleration, a is half of accelerating due to gravity, g.

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2 years ago

When the heater blows hot air around to heat your house, this is an example of heat being transferred by, A. Convection B. Conud

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4 years ago

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A ball is kicked at 30.0 m/s at an angle of 20.0°. Beneath the tilted columns calculate the vertical and horizontal components.

RSB [31]

The velocities at time t are

• Horizontal:

v = (30.0 m/s) cos(20.0º)

• Vertical:

v = (30.0 m/s) sin(20.0º) - g t

(where g = 9.80 m/s² is the magnitude of the acceleration due to gravity)

If you only want the initial velocities, they are

• Horizontal:

v = (30.0 m/s) cos(20.0º) ≈ 28.2 m/s

• Vertical:

v = (30.0 m/s) sin(20.0º) ≈ 10.3 m/s

(just set t = 0)

As far as starting equations go, you can derive everything from the definition for average acceleration:

a = ∆v / ∆t = (final v - initial v) / t

→ v = u + a t

(here, u stands in for "initial v" and v is simply velocity at time t )

There is no acceleration in the horizontal direction, while the ball is essentially in free-fall in the vertical direction.

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3 years ago

A spring has a 12 cm length. When a 200-g mass is hung from the spring, it extends to 27 cm. The hanging mass were pulled downwa

BartSMP [9]

Answer:

The equation of the time-dependent function of the position is $x(t)=5\cos(8.08t)$

(b) is correct option.

Explanation:

Given that,

Length = 12 cm

Mass = 200 g

Extend distance = 27 cm

Distance = 5 cm

Phase angle =0°

We need to calculate the spring constant

Using formula of restoring force

$F=kx$

$mg=kx$

$k=\dfrac{mg}{x}$

$k=\dfrac{200\times10^{-3}\times9.8}{(27-12)\times10^{2}}$

$k=13.06\ N/m$

We need to calculate the time period

Using formula of time period

$T=2\pi\sqrt{\dfrac{m}{k}}$

Put the value into the formula

$T=2\pi\sqrt{\dfrac{0.2}{13.6}}$

$T=0.777\ sec$

At t = 0, the maximum displacement was 5 cm

So, The equation of the time-dependent function of the position

$x(t)=A\cos(\omega t)$

Put the value into the formula

$x(t)=5\cos(2\pi\times f\times t)$

$x(t)=5\cos(2\pi\times\dfrac{1}{T}\times t)$

$x(t)=5\cos(2\pi\times\dfrac{1}{0.777}\times t)$

$x(t)=5\cos(8.08t)$

Hence, The equation of the time-dependent function of the position is $x(t)=5\cos(8.08t)$

8 0

3 years ago

How does The centripetal fotce change if the car has less Mass?​

How does The centripetal fotce change if the car has less Mass?