Answer: 53.09Hz
Explanation:
The fundamental frequency of an ideal taut string is:
Fn= n/2L(√T/μ)
Where:
F= frequency per second (Hz)
T= Tension of the string (cm/s sqr)
L= Length of the string (cm)
μ= Linear density or mass per unit length of the string in cm/gm
√T/μ= square root of T divided by μ
It is important to note:
Note: Typically, tension would be in newtons, length in meters and linear density in kg/m, but those units are inconvenient for calculations with strings. Here, the smaller units are used.
F1= 1/2(376cm)(0.01/1) × (√574/(0.036g/cm)(0.1kg/m÷1g/cm)
F1= 0.1329 × 399.30
= 53.09Hz
<span>k = 1.7 x 10^5 kg/s^2
Player mass = 69 kg
Hooke's law states
F = kX
where
F = Force
k = spring constant
X = deflection
So let's solve for k, the substitute the known values and calculate. Don't forget the local gravitational acceleration.
F = kX
F/X = k
115 kg* 9.8 m/s^2 / 0.65 cm
= 115 kg* 9.8 m/s^2 / 0.0065 m
= 1127 kg*m/s^2 / 0.0065 m
= 173384.6154 kg/s^2
Rounding to 2 significant figures gives 1.7 x 10^5 kg/s^2
Since Hooke's law is a linear relationship, we could either use the calculated value of the spring constant along with the local gravitational acceleration, or we can simply take advantage of the ratio. The ratio will be both easier and more accurate. So
X/0.39 cm = 115 kg/0.65 cm
X = 44.85 kg/0.65
X = 69 kg
The player masses 69 kg.</span>
Natural selection, it's simply when one animal outsmarts the rest and lives on to reproduce and carry on it's traits, when the animals who have not adapted well do not have the chance to reproduce, and the population dies off.
