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sammy [17]
4 years ago
12

Which term best describes how light waves from a star are affected as the star moves toward earth?

Physics
1 answer:
marta [7]4 years ago
6 0

Answer:

C. Blueshift

"If a star is moving towards the earth, its light is shifted to higher frequencies on the color spectrum (towards the green/blue/violet/ultraviolet/x-ray/gamma-ray end of the spectrum). A higher frequency shift is called a "blue shift"

Source: http://wtamu.edu/~cbaird/sq/2013/06/27/have-astronomers-ever-observed-a-violet-shift-like-they-have-blue-shifts-and-red-shifts/

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What property is primarily responsible for determining the type of electromagnetic energy and peak wavelength emitted by a star
Galina-37 [17]

Answer:<u><em>B. Temperature</em></u>

Explanation:The temperature of the star such as Sun is measured. Using this measurement, its peak wavelength and energy can be determined.For determination of wavelength, <u>Wien's displacement law is used</u>. This law states that, the sun like body emits all kinds of wavelengths and thus is nearly a black body.For black body, the peak wavelength emitted is inversely proportional to the temperature of the body. From the wavelength, energy can be calculated.<u>Temperature is the property which is primarily responsible for determining the type of electromagnetic energy and peak wavelength emitted by star</u>.

5 0
3 years ago
Which model is defined atomic model that describes an atom has a spherical object containing a certain number of electrons trapp
victus00 [196]

Answer:

C! Raisin Bread

Hope this helps you!

4 0
3 years ago
Read 2 more answers
A sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 35 km/h at the 67-m mar
xz_007 [3.2K]

Answer:

0.705 m/s²

Explanation:

a) The sprinter accelerates uniformly from rest and reaches a top speed of 35 km/h at the 67-m mark.

Using newton's law of motion:

v² = u² + 2as

v = final velocity = 35 km/h = 9.72 m/s, u = initial velocity = 0 km/h,  s = distance = 67 m

9.72² = 0² + 2a(67)

134a = 94.484

a = 0.705 m/s²

b) The sprinter maintains this speed of 35 km/h for the next 88 meters. Therefore:

v = 35 km/h = 9.72 m/s, u = 35 km/h = 9.72 m/s, s = 88 m

v² = u² + 2as

9.72² = 9.72² + 2a(88)

176a = 9.72² - 9.72²

a = 0

c) During the last distance, the speed slows down from 35 km/h to 32 km/h.

u = 35 km/h = 9.72 m/s, v = 32 km/h = 8.89 m/s, s = 200 - (67 + 88) = 45 m

v² = u² + 2as

8.89² = 9.72² + 2a(45)

90a = 8.89² - 9.72²

90a = -15.4463

a = -0.1716 m/s²

The maximum acceleration is 0.705 m/s² which is from 0 to 67 m mark.

8 0
3 years ago
A vaulter holds a 26.90-N pole in equilibrium by exerting an upward force U with her leading hand and a downward force D with he
ivolga24 [154]

Answer:

Check attachment for better understanding

Explanation:

Given that

a= 0.75m

b=1.31m

c= 2.2m

Weight of pole is 26.90

Then, Fg = Weight = 26.90

Using Equilibrium of forces

ΣFy = 0

U — D — Fg = 0

U — D = Fg

U — D = 26.9

To calculate U,

We will take moment about point A.

ΣMa = 0

Let the clockwise moment be positive and anti-clockwise be negative

Fg(a+b) — U(a) = 0

26.9(1.31+0.75) —0.75U = 0

26.9(2.06) = 0.75U

0.75U = 55.414

U = 55.414/0.75

U = 73.89 N

To calculate D,

U — D = 26.9

73.89—D =26.9

73.89—26.9 = D

D = 46.99N

3 0
3 years ago
Read 2 more answers
The time spent on design will vary, dependent on the complexity of the problem. Why is it important to give the design process a
lord [1]

Answer:To ensure significant dialogue which will guarantee that the needed Products meets specifications

It will help to develop a better Operational model for the users.

Explanation: The design phase is one of the most critical phase in product development,it is in this phase that the product structure, contents and specifications are put into action. It is necessary that the end users have a significant time to dialogue with the project or product development team to guarantee that the end product meets specifications.

It is also necessary to spent adequate time in order to make the product user friendly (easy to operate and maintain).

3 0
4 years ago
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