(a) The proton’s potential energy change is 3.6 x 10⁻¹⁸ J.
(b) The potential difference between the negative plate and a point midway between the plates is 11.25 V.
(c) The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.
<h3>
Potential energy of the proton</h3>
U = qΔV
where;
- q is charge of the proton
- ΔV is potential difference
U = q(Ed)
U = (1.6 x 10⁻¹⁹)(1500 x 1.5 x 10⁻²)
U = 3.6 x 10⁻¹⁸ J
<h3>Potential difference between the negative plate and a point midway</h3>
ΔV = E(0.5d)
ΔV = 0.5Ed
ΔV = 0.5 (1500)(1.5 x 10⁻²)
ΔV = 11.25 V
<h3>Speed of the proton </h3>
U = ¹/₂mv²
U = mv²
v² = 2U/m
where;
- m is mass of proton = 1.67 x 10⁻²⁷ kg
v² = (2 x 3.6 x 10⁻¹⁸) / ( 1.67 x 10⁻²⁷)
v² = 4.311 x 10⁹
v = √(4.311 x 10⁹)
v = 6.57 x 10⁴ m/s
Thus, the proton’s potential energy change is 3.6 x 10⁻¹⁸ J.
The potential difference between the negative plate and a point midway between the plates is 11.25 V.
The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.
Learn more about potential difference here: brainly.com/question/24142403
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Answer:
F = 0.64 N
Explanation:
We are given;
Spring constant constant; k = 1.28 N/m
Distance; x = 0.5 m
From Hooke's law, we know that F = kx.
Thus;
F = 1.28 × 0.5
F = 0.64 N
Thus, force it takes to pull the spring back = 0.64 N
The two types of mechanical waves are longitudinal waves, and transversal waves.
The amount of energy needed to increase the temperature of a substance by
is given by
where
m is the mass of the substance
is its specific heat capacity
is the increase in temperature
The water volume is
, since its density is
, the mass of this sample of water is
The water specific heat capacity is
and the increase in temperature is
Therefore, the amount of energy needed is
The answer is wave.
A wave can be defined as a rhythmic flow that moves over a medium from one place to the different area.
