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3 years ago

Which of the following is an example of a contact force?

Chemistry

2 answers:

Virty [35]3 years ago

7 0

C. A person pushing a box across the floor

MAXImum [283]3 years ago

5 0

I believe it would be C. A person pushing a box across the floor because it is the only thing that uses direct contact to apply a force, which is the definition of a contact force

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HEYYY FAM IS THIS RIGHT

Otrada [13]

Answer: A reversible reaction is a reaction that takes place in back and front directions. If the reaction were to reach equilibrium, the rate of forward direction would be equal to that of the reverse reaction.

Explanation:

Reversible reactions :

These are the reaction in which reactants reacts to give product and products reacts to give reactants as a product in return.

$A+B\leftrightharpoons C+D$

In above equation, 'A' and 'B' are reacting together to give 'C' and 'D', as products and vice-versa.
When the above reaction reaches equilibrium the rate of forward and backward reaction becomes equal.

3 0

3 years ago

Predict the sign of ΔS for each process:(c) Cl₂(g) (100°C and 1 atm) → Cl₂(g) (10°C and 1 atm)

dexar [7]

The entropy for the process:

Cu(s) (350°C and 2.5 atm) → Cu(s) (450°C and 2.5 atm) decreases. The sign of entropy is negative.

<h3>What is Entropy? </h3>

Entropy is defined as the measure of the thermal energy of a system per unit temperature which is unavailable for doing useful work. As the work is obtained from ordered molecular motion, therefore the amount of entropy is also gives a measure of the molecular disorder, or randomness, of a system.

<h3>Effect of Temperature</h3>

There is increase in the Entropy as temperature increases. An increase in the temperature results that particles of substance have greater kinetic energy. The fast moving particles have more disorder than particles which are moving slowly at the given lower temperature.

<h3>Effect of Pressure</h3>

The entropy increases with increases in the pressure on the substance.

Since the temperature of given reaction decreases. So, entropy also decreases.

Thus, we concluded that the entropy for the process:

Cu(s) (350°C and 2.5 atm) → Cu(s) (450°C and 2.5 atm) decreases. So, the sign of entropy is negative.

learn more about Entropy:

brainly.com/question/14131507

#SPJ4

7 0

2 years ago

What is one of the possible products of a solution if cai2 is mixed with a solution of nano3?

11Alexandr11 [23.1K]

Answer:
The two products that will be formed are:
Ca(NO3)2
NaI

Explanation:
When NaNO3 reacts with CaI2, double substitution reaction takes place.
This means that I2 and NO3 will each substitute the other.
The chemical reaction used to explain this is as follows:
2NaNO3 + CaI2 .........> 2NaI + Ca(NO3)2

Hope this helps :)

7 0

4 years ago

How many ozone particles are needed to form 24 particles of oxygen gas?

bearhunter [10]

First, you have to know the chemical formula of ozone and oxygen gas. Oxygen gas is O₂; it is one of the few gases that are diatomic in nature. The chemical formula of ozone is O₃. In oxygen gas, there are 2 particles of the oxygen element, while there are 3 particles for the ozone. There might be a slight difference but this induces a great difference in their properties. Oxygen is essential to living things because this is the gas that we breathe in. However, ozone is not safe to breathe in. It is a very strong oxidizing agent, almost 4 times as strong as the oxygen. Its main function is to block the UV rays from entering the Earth's atmosphere which can be harmful to our health.

Having known their chemical formula and properties, we know that an oxygen gas has 2 particles of oxygen element. So, if there are 24 particles of oxygen gas, that would mean 48 particles of the oxygen element. Since an ozone compound contains 3 particles of the oxygen element, then 48/3 = 16. It would take 16 particles of ozone to form 24 particles of the oxygen gas.

6 0

3 years ago

How to make 100 ml of 0.001 mM solution with 0.0405mM solution?

alexgriva [62]

Answer:

Measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water

Explanation:

To make 100 mL of 0.001 mM solution from 0.0405mM solution, we need to determine the volume of 0.0405mM solution needed. This can be obtained as follow:

Molarity of stock (M₁) = 0.0405 mM

Volume of diluted (V₂) = 100 mL

Molarity of diluted solution (M₂) = 0.001 mM

Volume of stock solution needed (V₁) =?

M₁V₁ = M₂V₂

0.0405 × V₁ = 0.001 × 100

0.0405 × V₁ = 0.1

Divide both side by 0.0405

V₁ = 0.1 / 0.0405

V₁ = 2.47 mL

Therefore, to make 100 mL of 0.001 mM solution from 0.0405mM solution, measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water.

3 0

3 years ago