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S_A_V [24]
3 years ago
9

HEYYY FAM IS THIS RIGHT

Chemistry
1 answer:
Otrada [13]3 years ago
3 0

Answer: A reversible reaction is a reaction that takes place in back and front directions. If the reaction were to reach equilibrium, the rate of forward direction would be equal to that of the reverse reaction.

Explanation:

Reversible reactions :

These are the reaction in which reactants reacts to give product and products reacts to give reactants as a product in return.

        A+B\leftrightharpoons C+D

  • In above equation, 'A' and 'B' are reacting together to give 'C' and 'D', as products and vice-versa.
  • When the above reaction reaches equilibrium the rate of forward and backward reaction becomes equal.




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Calcutale Grxn for the following equation at 25°C: <br><br> 4KClO3(s) → 3KClO4(s) KCl(s)
Step2247 [10]

Answer:

-133.2 kJ

Explanation:

Let's consider the following balanced equation.

4 KClO₃(s) → 3 KClO₄(s) + KCl(s)

We can calculate the standard Gibbs free energy of the reaction (ΔG°rxn) using the following expression.

ΔG°rxn = 3 mol × ΔG°f(KClO₄(s)) + 1 mol × ΔG°f(KCl(s)) - 4 mol × ΔG°f(KClO₃(s))

ΔG°rxn = 3 mol × (-303.1 kJ/mol) + 1 mol × (-409.1 kJ/mol) - 4 mol × (-296.3 kJ/mol)

ΔG°rxn = -133.2 kJ

5 0
3 years ago
An internal combustion engine relies primarily on the efficient production of energy by the combination of oxygen (02) and gasol
jeka57 [31]
Answer is: <span>the exact ratio of oxygen to octane for is 12.5 : 1.
</span>Balanced chemical reaction: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O or multiply by 2:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O.
There same number of atoms on both side of balanced chemical reaction: eight carbon atoms, eighteen hydrogen atoms and twenty five oxygen atoms.

7 0
3 years ago
The heat of combustion of ethane is -337.0kcal at 25 degrees celsius. what is the heat of the reaction when 3g of ethane is burn
Ghella [55]

Answer:

Q = -33.6kcal .

Explanation:

Hello there!

In this case, according to the equation for the calculation of the total heat of reaction when a fixed mass of a fuel like ethane is burnt, we can write:

Q=n*\Delta _cH

Whereas n stands for the moles and the other term for the enthalpy of combustion. Thus, for the required total heat of reaction, we first compute the moles of ethane in 3 g as shown below:

n=3g*\frac{1mol}{30.08g}=0.1mol

Next, we understand that -337.0kcal is the heat released by the combustion of 1 mole of ethane, therefore, to compute Q, we proceed as follows:

Q=0.1mol*-337.0\frac{kcal}{mol}\\\\Q=-33.6kcal

Best regards!

8 0
2 years ago
A or B or C or D, fassst plzzz
olga nikolaevna [1]

Answer:

a.option is the correct answer

4 0
2 years ago
Read 2 more answers
What is the electron structure of sodium
yarga [219]
Electron structure of sodium:
₁₁Na: 1s²2s²2p⁶3s¹
8 0
3 years ago
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