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scZoUnD [109]
1 year ago
12

Predict the sign of ΔS for each process:(c) Cl₂(g) (100°C and 1 atm) → Cl₂(g) (10°C and 1 atm)

Chemistry
1 answer:
dexar [7]1 year ago
7 0

The entropy for the process:

Cu(s) (350°C and 2.5 atm) → Cu(s) (450°C and 2.5 atm) decreases. The sign of entropy is negative.

<h3>What is Entropy? </h3>

Entropy is defined as the measure of the thermal energy of a system per unit temperature which is unavailable for doing useful work. As the work is obtained from ordered molecular motion, therefore the amount of entropy is also gives a measure of the molecular disorder, or randomness, of a system.

<h3>Effect of Temperature</h3>

There is increase in the Entropy as temperature increases. An increase in the temperature results that particles of substance have greater kinetic energy. The fast moving particles have more disorder than particles which are moving slowly at the given lower temperature.

<h3>Effect of Pressure</h3>

The entropy increases with increases in the pressure on the substance.

Since the temperature of given reaction decreases. So, entropy also decreases.

Thus, we concluded that the entropy for the process:

Cu(s) (350°C and 2.5 atm) → Cu(s) (450°C and 2.5 atm) decreases. So, the sign of entropy is negative.

learn more about Entropy:

brainly.com/question/14131507

#SPJ4

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m_{soluto}=60g

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¡Hola!

En este caso, al considerar la unidad de concentración de porcentaje masa/masa, podemos escribir su fórmula como:

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Podemos identificar la masa de soluto (azúcar) como la incógnita, y resolverla como se muestra a continuación:

m_{soluto}=\frac{\%m/m*m_{solucion}}{100\%}\\\\m_{soluto}=\frac{20\%*300g}{100\%}\\\\m_{soluto}=60g

¡Saludos!

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