Question

A kite is flying at an angle of elevation of about 40 degrees. all 80 m of string have been let out. ignoring the sag in the string, find the height of the kite to the nearest 10 m.

Answer 1

Sin 40° = h / 80 m
0.6427876 = h / 80 m
h = 0.6427876 · 80 m
h = 51.423 m ≈ 50 m ( to the nearest 10 m )
Answer:
The height of the kite is about 50 m.