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Dima020 [189]
3 years ago
13

An electron moved from shell n = 2 to shell n = 1. What most likely happened during the transition?

Chemistry
2 answers:
mihalych1998 [28]3 years ago
7 0

Answer:  A photon of energy was released.

mariarad [96]3 years ago
5 0

Answer: A photon of energy was released.

Explanation: The energy of the orbitals keep on increasing as the size of the orbitals keep on increasing or the value of n keeps on increasing.

The electrons absorb energy when they are irradiated or put at high temperatures and move to higher energy states. The electrons then get back to their ground state by releasing energy in the form of radiations. Thus when an electron move from n = 2 to shell n = 1, the absorbed energy is given off in form of photons of energy.

Energy is released or absorbed in the form of discrete packets of energy called as photons.

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How can a hydrogen atom, which has only one electron, have so many spectral lines?
kow [346]

Answer:

The hydrogen atom has just one electron, but many spectral lines. However it contains many shells and the movement of that electron from one shell to another causes the release of energy and also an emission of photons.

A spectral line are dark or bright lines formed within a specific frequency range which differ from other frequencies.Because of the difference of energy for the various shells, it produces different wavelengths and this is the reason for the many spectral line for hydrogen.

6 0
3 years ago
Identify the arrows that show removal of thermal energy when matter changes state.
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Let's identify first the phases of matter inside each of those beakers. The first beaker on the left has a compact shape and has its own volume. So, that must be solid. The middle beaker has a compact shape but it takes the shape of its container. So, that must be liquid. The third beaker on the right is gas because the molecules are far away from each other.

After identifying each states, let's investigate the energy for phase change. Let's start with the arrows pointing to the right. The first arrow to the right is a phase change from solid to liquid. The intermolecular forces in a solid is the strongest among the three phases of matter. So, you would need an input of energy to break them apart into liquid. The same is true for the phase change from liquid to gas. Therefore, all the arrows pointing to the right require an input of energy.

The reverse arrows pointing to the left needs to release energy. The molecules in the gas state are free such that they can travel from one point to another easily. They have the highest amount of energy. So, if you want the molecules to come closer together, you need to remove the energy to keep them in place. Therefore, the arrows pointing to the right require removal of energy.
7 0
3 years ago
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Sodium thiosulfate, Na 2S 2O 3, is used as a "fixer" in black and white photography. Identify the reducing agent in the reaction
Tatiana [17]

Answer: Reducing agent in the given reaction is S_{2}O^{2-}_{3}.

Explanation:

A reducing agent is defined as an element which tends to lose electrons to other element leading to an increase in its oxidation number.

In the given reaction, oxidation state of sulfur in S_{2}O^{2-}_{3} is +2 and I_{2}(aq) has 0 oxidation state.

In S_{4}O^{2-}_{6}(aq) oxidation state of S is 2.5 and in 2I^{-}(aq) oxidation state of I is -1.

Since, an increase in oxidation state of S is occurring from +2 to +2.5. Hence, it is acting as a reducing agent.

Thus, we can conclude that reducing agent in the given reaction is S_{2}O^{2-}_{3}.

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