The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C
<h3>How to calculate temperature?</h3>
The initial temperature of the copper metal can be calculated using the following formula on calorimetry:
Q = mc∆T
mc∆T (water) = - mc∆T (metal)
Where;
- m = mass
- c = specific heat capacity
- ∆T = change in temperature
According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:
400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)
30,096 = 93.6T - 2246.4
93.6T = 32342.4
T = 345.5°C
Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.
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Answer:
D.Geologists use data from three or more data stations to determine the location of the epicenter.
Rounded to 1 significant figure, 25 m would go to 30. This is because 0 isn't significant, so the 3 is the only significant figure.
Answer:
The absorbance of the myoglobin solution across a 1 cm path is 0.84.
Explanation:
Beer-Lambert's law :
Formula used :
where,
A = absorbance of solution
c = concentration of solution
= Molar absorption coefficient
l = path length
= incident light
= transmitted light
Given :
l = 1 cm, c = 1 mg/mL ,
Molar mass of myoglobin = 17.8 kDa = 17.8 kg/mol=17800 g/mol
(1 Da = 1 g/mol)
c = 1 mg /mL = 
1 mg = 0.001 g, 1 mL = 0.001 L
The absorbance of the myoglobin solution across a 1 cm path is 0.84.
