The number is 33 because 24 + 9 = 33
Atomic mass calcium ( Ca ) = 40.078 a.m.u
40.078 g ------------- 6.02x10²³ atoms
165 g ----------------- ??
165 x ( 6.02x10²³ ) / 40.078
=> 2.47x10²⁴ atoms
Answer:
![W=-4601.4J](https://tex.z-dn.net/?f=W%3D-4601.4J)
Explanation:
Hello,
In this case, the steps are:
![291K,1.50bar, 13.3L \rightarrow 15.0bar 13.3L,T_2\rightarrow T_2, V_2, 1.50bar\rightarrow 291K,1.50bar, 13.3L](https://tex.z-dn.net/?f=291K%2C1.50bar%2C%2013.3L%20%5Crightarrow%2015.0bar%2013.3L%2CT_2%5Crightarrow%20T_2%2C%20V_2%2C%201.50bar%5Crightarrow%20291K%2C1.50bar%2C%2013.3L)
In such a way, the work per mole (w) for that isothermal process turns out:
![w=RTln(\frac{P_1}{P_2} )=8.314\frac{J}{mol*K}*291K*\frac{1.50bar}{15.0bar} \\\\w=-5570.8\frac{J}{mol}](https://tex.z-dn.net/?f=w%3DRTln%28%5Cfrac%7BP_1%7D%7BP_2%7D%20%29%3D8.314%5Cfrac%7BJ%7D%7Bmol%2AK%7D%2A291K%2A%5Cfrac%7B1.50bar%7D%7B15.0bar%7D%20%5C%5C%5C%5Cw%3D-5570.8%5Cfrac%7BJ%7D%7Bmol%7D)
In addition, if the moles are required, since it is an ideal gas:
![n=\frac{PV}{RT}=\frac{1.50bar*13.3L}{0.083\frac{bar*L}{mol*K}*291K} =0.826mol](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BPV%7D%7BRT%7D%3D%5Cfrac%7B1.50bar%2A13.3L%7D%7B0.083%5Cfrac%7Bbar%2AL%7D%7Bmol%2AK%7D%2A291K%7D%20%3D0.826mol)
So the work is:
![W=-5570.8\frac{J}{mol} *0.826mol=-4601.4J](https://tex.z-dn.net/?f=W%3D-5570.8%5Cfrac%7BJ%7D%7Bmol%7D%20%2A0.826mol%3D-4601.4J)
Best regards.
Answer:
2930 mmHg
Explanation:
We need to convert these two different units of pressure into the same. Let's just use mmHg. So, we need to go from atm to mmHg. The conversion factor is 1 atm = 760 mmHg. We have 5.50 atm, so multiply 760 by 5.50: 4180 mmHg.
Now, partial pressure means that the pressures of each of the different gases will add up to the total pressure. Here, our total pressure is 4180 mmHg and the pressure of oxygen is 1250 mmHg. So to find the pressure of hydrogen, we simply subtract 1250 from 4180: 4180 - 1250 = 2930 mmHg.
Hope this helps!
Clear glass, water, and air are examples of transparent material. They can be seen through with no extra factors or complications. Therefore, your answer would be D. transparent.