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tatuchka [14]
3 years ago
8

Identify the arrows that show removal of thermal energy when matter changes state.

Chemistry
2 answers:
8090 [49]3 years ago
7 0
Let's identify first the phases of matter inside each of those beakers. The first beaker on the left has a compact shape and has its own volume. So, that must be solid. The middle beaker has a compact shape but it takes the shape of its container. So, that must be liquid. The third beaker on the right is gas because the molecules are far away from each other.

After identifying each states, let's investigate the energy for phase change. Let's start with the arrows pointing to the right. The first arrow to the right is a phase change from solid to liquid. The intermolecular forces in a solid is the strongest among the three phases of matter. So, you would need an input of energy to break them apart into liquid. The same is true for the phase change from liquid to gas. Therefore, all the arrows pointing to the right require an input of energy.

The reverse arrows pointing to the left needs to release energy. The molecules in the gas state are free such that they can travel from one point to another easily. They have the highest amount of energy. So, if you want the molecules to come closer together, you need to remove the energy to keep them in place. Therefore, the arrows pointing to the right require removal of energy.
Phantasy [73]3 years ago
4 0

Answer: the arrows pointing to the right show removal of thermal energy

Explanation: plato

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The storage and transport of material takes place in the ________.
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The blank is - <span>Endoplasmic reticulum</span>
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4 years ago
What is the density of water if you have 50.0 grams of water and a volume of 50.0 millimeters
Gnom [1K]

Answer:

\boxed {\tt 1.0 \ g/mL}

Explanation:

Density can be found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the water is 50.0 grams.

The volume of the water is 50.0 milliliters.

m= 50.0\ g \\v=50.0 \ mL

Substitute the values into the formula.

d=\frac{50.0 \ g}{50.0 \ mL}

Divide.

d= 1.0  \ g/mL

The density of the water is 1.0 grams per milliliter. Also, remember that the density of pure water is always 1.0 g/mL or g/cm³

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3 years ago
Energy conversion means reducing energy use True or false
I am Lyosha [343]
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3 years ago
What is the concentration of bromide, in ppm, if 12.41 g MgBr2 is dissolved in 2.55 L water.
pav-90 [236]

Answer:

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

Explanation:

ppm (parts per million) concentration is defined as the mass (in milligrams) of a substance dissolved in one liter of solution.

In our case we have:

mass of MgBr₂ = 12.41 g

volume of water (which is equal to the final solution volume) = 2.55 L

Now we devise the following reasoning:

if         12.41 g of MgBr₂ are dissolved in 2.55 L of water

then         X g of MgBr₂ are dissolved in 1 L of water

X = (1 × 12.41) / 2.55 = 4.867 g of MgBr₂

if in         184 g (1 mole) of MgBr₂ we have 160 g of Br⁻

then in   4.867 g of MgBr₂ we have Y g of Br⁻

Y = (4.867 × 160) / 184 = 4.232 g of bromide (Br⁻)

4.232 g of bromide (Br⁻) = 4234 mg of bromide (Br⁻)

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

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Can you give the specific problem?
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3 years ago
Read 2 more answers
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