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igomit [66]
2 years ago
6

Calculate the number of grams of ethanol nevessary to prepare 268g of a 9.76m solution of ethanol in water

Chemistry
1 answer:
stiv31 [10]2 years ago
7 0

The amount, in grams, of ethanol needed to prepare 268 grams of a 9.76 M solution of ethanol in water will be 120.50 grams

<h3>Solution preparation</h3>

In order to prepare 268 grams of solution, 268 mL of water would be needed because 1 mL of water weighs 1 gram.

Since we now know the volume of solution that we want to prepare, the amount of solute (ethanol) that would be required in order to make a solution of 9.76 M will be:

Mole required = 9.76 x 268/1000 = 2.62 moles

Mass of 2.62 moles ethanol = 2.62 x 46.07 = 120.50 grams

More on solution preparation can be found here: brainly.com/question/14667249

#SPJ3

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___AsCl3+____H2S--&gt;___As2S3+___HCI​
Alex17521 [72]

Answer:

2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl

Explanation:

When we balance a chemical equation, what we are trying to do is to achieve the same number of atoms for each element on both sides of the arrow. On the right of the arrow is where we can find the products, while the reactants are found on the left of the arrow.

We usually balance O and H atoms last.

AsCl₃ + H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 1

Cl --- 3

H --- 2

S --- 1

<u>products</u>

As --- 2

Cl --- 1

H --- 1

S --- 3

2 AsCl₃ + H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 2

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H --- 2

S --- 1

<u>products</u>

As --- 2

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The number of As atoms is now balanced.

2 AsCl₃ + 3 H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

<u>products</u>

As --- 2

Cl --- 1

H --- 1

S --- 3

The number of S atoms is now equal on both sides.

2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl

<u>reactants</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

<u>products</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

The equation is now balanced.

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