Question

There is a basketball with a diameter of 9in. and a softball with a diameter of 4in. Find how many times greater the volume of the basketball is as that of the softball.

Answer 1

Explanation:

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Answer 2

Answer: #.37 times greater

Explanation: Volume of a sphere is: V = $\frac{4}{3}$·π·r³

Since it is given the diameter of the basketball and the softball, their ratios are r₁ = 3in and r₂ = 2in, in which index 1 represents the basketball and index 2, the softball.

Calculating the volume of basketball:

V₁ = $\frac{4}{3}$ . 3.14 . 3³

V₁ = 113.04 in³

Calculating the volume of softball:

V₂ = $\frac{4}{3}$ . 3.14 . 2³

V₂ = 33.5 in³

Comparing one volume with the other:

$\frac{V1}{V2}$ = $\frac{113.04}{33.5}$ = 3.37

We have that V₁ = 3.37V₂

This means the volume of a basketball is 3.37 times greater than the volume of a softball.