Answer:
where L is the length of the ramp
Explanation:
Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.
The parallel component would have a magnitude of
We can use the following equation of motion to find out the final velocity of the book after sliding L m:
where v m/s is the final velocity, 
= 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and 
is the distance traveled:
Answer:
D) 11 N
Explanation:
F = mg
In the vertical
30 = m(9.8)
m = 3.06 kg
in the horizontal
F = ma
F(unknown) - 5 = 3.06(2.0)
F(unknown) = 11.12... N
So, for the visible range, the colors are arranged in order of increasing frequency like this: Red < Orange<span> < </span>Yellow<span> < Green < Blue < Indigo < </span>VIolet<span>.</span>
Answer: 4.9 x 10-3 N
Explanation:
A = 500cm^2 = 5 x 10^-2 m^2
V = 5 m/s
R = 10^-3 g/cm^2.sec = 10^-2kg/m^2 . sec
Prain water = R / V = 10^-2 / 5 = 2 x 10-3 kg/m^3
For the stationary bowl,
dm/dt =pAv= RA
F= dp/dt = (dm/dt) v = RAv = 2.5 x 10^-3 N
Bowl moving upwards to speed u = 2 m/s
dm/dt = pA ( v + u) / v
F = dp/dt = (dm/dt)(v+u) = RA (v+u)^2 / v = 4.9 x 10^-3 N
Answer and Explanation:
with reference to Einstein's theory of special relativity, the speed of an electromagnetic radiation, here, laser will not change in any inertial frame or remains same irrespective of any change in inertial frame.
Therefore, the speed of light measured in both the cases, i.e., in astronaut's reference frame and spaceship's reference frame will be equal to the speed of light in vacuum, i.e., 
.
The laser gun's speed in astronaut's reference frame is the same as the speed of the spaceship as it mounted on it, i.e., the speed of the laser gun is 200 million m/s.
The laser gun's speed measured in spaceship's reference frame will be zero, as it is mounted on the spaceship and is stationary in the spaceship's reference frame.
