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Fudgin [204]
3 years ago
11

When rust forms on a piece of iron, what evidence do you have that a chemical reaction has taken place??

Chemistry
1 answer:
-BARSIC- [3]3 years ago
7 0

Answer:

You know that a chemical reaction has taken place because there is a material a color change.

Explanation:

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AVprozaik [17]

Answer:

The answer is b

Explanation:

Hope it helps

8 0
3 years ago
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Brodation<br>number of oxygen in F2O is.​
larisa86 [58]

Answer:

Oxidation number of F2O = 0−(−1×2)

State of oxygen will be=+2

4 0
3 years ago
Mention the reason why aquatic plants have air filled tissues.​
Pepsi [2]

Answer:

Aquatic plants have aur filled tissues to make them easy to float.....

Explanation:

It provides buoyancy

7 0
3 years ago
The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?
anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

K_a\times K_b=K_w

K_b for sodium formate is K_b=\frac {K_w}{K_a}

Given that:

K_a of formic acid = 1.8\times 10^{-4}

And, K_w=10^{-14}

So,

K_b=\frac {10^{-14}}{1.8\times 10^{-4}}

K_b=5.5556\times 10^{-11}

Concentration = 0.35 M

HCOONa    ⇒     Na⁺ +    HCOO⁻

Consider the ICE take for the formate  ion as:

                                   HCOO⁻ + H₂O   ⇄   HCOOH + OH⁻

At t=0                              0.35                            -              -

At t =equilibrium           (0.35-x)                          x           x            

The expression for dissociation constant of sodium formate is:

K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}

5.5556\times 10^{-11}=\frac {x^2}{0.35-x}

Solving for x, we get:

x = 0.44×10⁻⁵  M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

<u>pH = 14 - 4.64 = 9.36</u>

5 0
3 years ago
Terry, a student, performs a titration. He completes these steps as part of his titration procedure: 1. He cleans and rinses a b
Contact [7]

Answer:

D

Explanation:

D is the answer because 2 is needed to know

6 0
3 years ago
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