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dexar [7]
3 years ago
15

Nuclei with ______ numbers of neutrons and protons are more stable . A low

Chemistry
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer: equal

Explanation:

I believe the answer is equal but i would need more context.

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What mass of oxygen is required to completely react with 2 moles of ch4
Firlakuza [10]
The balanced reaction that describes the reaction between methane and oxygen to produce water and carbon dioxide is expressed CH4  + 2 O2 = CO2 +2H2O. Hence for 2 moles of methane used, 4 moles of oxygen are needed to react completely.
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2 years ago
The water cycle, photosynthesis, nutrient cycling, and soil formation are examples of:
mixas84 [53]

It seems like the answer would be supporting services.

8 0
2 years ago
How mant grams are there in 7.15 x 10^24 molecules of water?
worty [1.4K]

Answer:

B. 214.02

Explanation:

1 mol of water weighs 18.015 gm and contains 6.023 × 10²³ molecules

From question, We have 7.15 × 10²⁴ molecules

Dividing we get (7.15 × 10 ²⁴) ÷ ( 6.023 × 10²³) = 11.871 molecules

Now, Weight of water = 11.871 × 18.015 = 213.85 which is nearer to option B

4 0
2 years ago
Read 2 more answers
108/49 In ? 108/48 Cd + ? In the equation above, what particle or type of radiation needs to be included on the right hand side
Oksanka [162]

Answer: b) positron

Explanation:

The antiparticle or the antimatter counterpart of the electron is called positron.

The positron has an electric charge of +1 e and same mass as an electron. When a positron collides with an electron, annihilation takes place.

Below is an attachnent that further explains this

7 0
2 years ago
A hypothetical covalent molecule, X–Y, has a dipole moment of 1.93 1.93 D and a bond length of 109 pm. 109 pm. Calculate the par
Gnesinka [82]

Answer:

q= 110.5 ke

Explanation:

Dipole moment is the product of the separation of the ends of a dipole and the magnitude of the charges.

μ = q * d

μ= Dipole moment (1.93 D)

q= partial charge on each pole

d= separation between the poles(109 pm).

e= electronic charge ( 1.60217662 × 10⁻¹⁹ coulombs)

So,

q= \frac{1.93}{109 * 10^{-12} } coulombs

q = \frac{1.93}{109 * 10^{-12} *  1.60217662 * 10^{-19} } e

q = 1.105 * 10⁵ e

q= 110.5 ke

4 0
3 years ago
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